Find the slope of the line passing through the points (4, 4) and (4, - 4) .

Mathematics

1 answer:

sveticcg [70]2 years ago

3 0

Answer:

Slope = undefined

Step-by-step explanation:

We know that:

Slope Formula = y₂ - y₁/x₂ - x₁

Solution:

y₂ - y₁/x₂ - x₁ = -4 - 4/4 - 4
=> -8/0 = undefined

Since the slope of the line is un-defined, the line is vertical. Please look at my graph to understand better.

You might be interested in

2y=x+6 2y-x=6 how do i solve following the system of equations

Margarita [4]

$2y = x + 6 \\ \\ 1. \: 2y - 6 = x \\ 2. \: x = 2y - 6 \\ \\ \\ 2y - x = 6 \\ \\ 1. \: - x = 6 - 2y \\ 2. \: x = - 6 + 2y \\ 3. \: x = 2y - 6$

7 0

2 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$