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damaskus [11]
3 years ago
12

How many solutions can be found for the equation 3z + 2[z - 3) = 7z+12

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
7 0
<h2><u>Given</u> :-</h2>

3z + 2(z - 3) = 7z + 12

<h2><u>Solution</u> :-</h2>

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9

\\

Answered by - ItzMaster

Verizon [17]3 years ago
3 0
<h2><u>Given</u> :-</h2>

3z + 2(z - 3) = 7z + 12

<h2><u>Solution</u> :-</h2>

3z + 2(z - 3) = 7z + 12

3z + 2z - 6 = 7z + 12

3z + 2z - 7z = 12 + 6

5z - 7z = 18

-2z = 18

z = 18/2

z = 9

\\

Answered by - ItzAdmire

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