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3 years ago

Please help!!!!! Thank you

Mathematics

1 answer:

marin [14]3 years ago

7 0

Its 872 when the integer goes down

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* Easy 20 points! Will mark Brainliest!*

Ket [755]

Y = 72.3x
72.3 - 39.1 = 33.2

7 0

3 years ago

Read 2 more answers

1/8 divided by 5 pls help

timofeeve [1]

Answer:

1/40

Step-by-step explanation:

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6 0

3 years ago

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A rectangular garden has a length that is

skelet666 [1.2K]

Answer:

Since,

Length is 4 times Breadth

Let Breadth be x

Therefore,Length=4x

Perimeter=50m

Therefore,

50m=2(l+b)

50m=2(4x+x)

50m=2(5x)

50m=10x

x=5m.

Therefore,

Breadth=5m

Length=4x=4×5=20m

6 0

3 years ago

Question 1 of 5

mario62 [17]

The answer is 2 answer 2

4 0

3 years ago

(1 point) Use the graph below to find exact values of the indicated derivatives, or state that they do not exist. If a derivativ

svetlana [45]

Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

$\mathbf{h(x) = f(g(x))}$

Start by calculating the equations of f(x) and g(x)

Graph f(x)

The slopes of f(x) are: 3/2 and -3/2

So, the equations are:

$\mathbf{f(x) = \frac{3}{2}x,\ 0 \le x \le 2}$

$\mathbf{f(x) = -\frac{3}{2}x,\ x \ge 2}$

Graph g(x)

The slope of g(x) is: -1/2

So, the equation is:

$\mathbf{g(x) = -\frac 12x}$

For x = 1 and x = 2, we have:

So, we have:

$\mathbf{h(x) = f(g(x))}$

Where:

$\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2}$ and $\mathbf{g(x) = -\frac 12x}$

$\mathbf{h(x) = f(g(x))}$ becomes

$\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}$

Open brackets

$\mathbf{h(x) = -\frac{3}{4}x}$

Differentiate

$\mathbf{h'(x) = -\frac{3}{4}}$

So:

$\mathbf{h'(1) = -\frac{3}{4}}$

$\mathbf{h'(2) = -\frac{3}{4}}$

For x = 3, we have:

$\mathbf{h(x) = f(g(x))}$

Where:

$\mathbf{f(x) = -\frac{3}{2}x\ x \ge 2}$ and $\mathbf{g(x) = -\frac 12x}$

$\mathbf{h(x) = f(g(x))}$ becomes

$\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}$

$\mathbf{h(x) = \frac{3}{4}x}$

Differentiate

$\mathbf{h'(x) = \frac{3}{4}}$

Substitute 3 for x

$\mathbf{h'(3) = \frac{3}{4}}$

Hence, the values of the derivatives are:

$\mathbf{h'(1) = -\frac{3}{4}}$ , $\mathbf{h'(2) = -\frac{3}{4}}$ and $\mathbf{h'(3) = \frac{3}{4}}$

Read more about graphed functions at:

brainly.com/question/11804653

3 0

3 years ago

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