Y = 5x + 2
3x = y + 10
3x = y + 10
3x = 5x + 2 + 10
3x = 5x + 12
3x - 5x = 12
-2x = 12
x = -6
substitute x = -6 into y = 5x + 2
y = 5(-6) + 2
y = -30 + 2
y = -28
x = -6, y = -28
hope this helped, God bless!
Answer:
67
Step-by-step explanation:
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer:
7/20
Step-by-step explanation:
75.89 + 0.12x = 27.41 + 0.36x
75.89 - 27.41 = 0.24x
48.48 = 0.24x
x = 48.48 / 0.24
x = 202
Each sent 202 text messages
