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Nadya [2.5K]
2 years ago
9

Bob's gift shop sold a record number of cards for Mother's Day. One salesman sold 33

Mathematics
1 answer:
sattari [20]2 years ago
6 0

Answer:

660

Step-by-step explanation:

33/0.05

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Select the two values of x that are roots of this equation.<br> 2x2 + 7x + 6 = 0
SVEN [57.7K]
Hopes this helps:

Answer: x = -10/7

1. Simplify 2 • 2 to 4
4 + 7x + 6 = 0

2. Simplify 4 + 7x + 6 to 7x + 10.
7x + 10 = 0

3. Subtract 10 from both sides.
7x = -10

4. Divide both sides by 7.
X = -10/7
3 0
2 years ago
Review: Key Concepts
inessss [21]

Answer:

Not helpful

Step-by-step explanation:

4 0
2 years ago
Fred wants to find 48+34 using compensation.He says you can take 2 from 34 and give it to 48 to make 50.What is the sum?Explain
Montano1993 [528]
It is easier to add 50 to a number than 48 because 50 has a zero in it which makes an addition simpler.

48 + 34 =     borrow 2 from 34 and add to 48

= 50 + 32      50 + 32 is 82

= 82
6 0
2 years ago
Spending 4$ every 5 min,in 6 days you'll spend how much?
grandymaker [24]
That is just a bunch if multiplying so let the fun begin
$4*(5*12*24*6) = $34,560
8 0
3 years ago
I need help with this Factoring Quadratics question.Can someone help me?
antoniya [11.8K]

If you mean "factor over the rational numbers", then this cannot be factored.

Here's why:

The given expression is in the form ax^2+bx+c. We have

a = 3

b = 19

c = 15

Computing the discriminant gives us

d = b^2 - 4ac

d = 19^2 - 4*3*15

d = 181

Note how this discriminant d value is not a perfect square

This directly leads to the original expression not factorable

We can say that the quadratic is prime

If you were to use the quadratic formula, then you should find that the equation 3x^2+19x+15 = 0 leads to two different roots such that each root is not a rational number. This is another path to show that the original quadratic cannot be factored over the rational numbers.

7 0
3 years ago
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