Answer:
B) h(x) = –2x + 200
Step-by-step explanation:
f(x) = 3x + 400
g(x) = 5x + 200
f(x) - g(x) = 3x + 400 - (5x + 200) = -2x + 200
Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
To find the volume of a container, you simply multiply: L(ength) x B(ase) x H(eight).
In total, you should get a volume of 1078in^3 (the bigger container) plus 175in^3 (the smaller container on top of the bigger one). The answer is 1,253in^3.
Hope this helped! :)
The total value is:
5. 5 x 10 ^5 * 23 x 10^3 =
= $126.5 * 10^8 =
= $1.265 x 10^10
Answer: B )
<span>Alright, here's your answer.
y-intercept is computed (not found) by assigning x = 0 and computing y: here that is f(0) = Log(2*0 + 1) – 1 = Log(1) – 1 = 0 – 1 = -1
y-intercept is (0, -1)
x-intercept is computed by solving f(x) = 0 for x: here that is
0 = Log(2x + 1) – 1 → 1 = Log(2x + 1)
Assuming the Log cited is base 10, then 10^1 = 10^Log(2x + 1) = 2x + 1
That’s 10 = 2x + 1
Therefore 9 = 2x
x = 9/2 = 4.5
Check this result in the original equation, I did!
Your answer is - x-intercept is (4.5, 0)
I hope I helped! :)
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