Answer:
this is not a equation.
Step-by-step explanation:
sorry. Do you mean y+7=-3x or something?
Answer:
what equation I don't see one
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
Compound interest = $365.4
Step-by-step explanation:
Given:
Amount borrowed = $6,000
Rate of interest = 3%
Number of year = year
Find:
Compound interest
Computation:
A = P[1+r]ⁿ
Amount after 2 year = 6,000[1 + 3%]²
Amount after 2 year = 6,000[1 + 0.03]²
Amount after 2 year = 6,000[1.03]²
Amount after 2 year = 6,000[1.0609]
Amount after 2 year = 6,365.4
Compound interest = Amount after 2 year - Amount borrowed
Compound interest = 6,365.4 - 6,000
Compound interest = $365.4
£7200
In first year depreciates by 20%, that is it is worth 80% of it's original value
80% = 
= 0.8
value after 1 year = 0.8 × £10000 = £8000
In the second year it depreciates by 10% of it's value, that is it is worth 90% of it's value at the end of the first year.
90% = 
= 0.9
value after 2 years = 0.9 × £8000 = £7200
