From the equation of motion, we know,

Where s= displacement
u= initial velocity
a= gravitational force
t= time
Displacement is 0 since the ball comes back to the same point from where it was thrown.
A =
since the ball is thrown upwards.
Plug the known values into the equation.
=> 
Solving for u gives :
u= 16.67 m/ sec ....... equation (1)
At maximum height, final velocity i.e v is 0
Time take to reach the top = 

=> 
Solving for s we get
s= 14.16 m
Answer:
2
Step-by-step explanation:
3(x+2)=12
Distribute:
3x+6=12
Subtract:
3x+6-6=12-6
3x=6
Divide:
x=2
56ft². <span>Surface Area = 2×(2×2 + 2×6 + 2×6)</span>
1 km = 1000m
1 hr = 3600 s
189 km/h
189 * 1000 / 3600 m/s
189*5/18 m/s
945/18 m/s
315/6 m/s
105/2 m/s
52.5 m/s
in 10 s
52.5*10
525 m
1 is not even yet it is a factor of 8. Alice is wrong.