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weeeeeb [17]
3 years ago
5

What do i have to multiply 5 with to get 7?​

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0

Answer:

1.4 (or 7/5)

Step-by-step explanation:

5x = 7

/5    /5

x = 1.4

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PLEASE HELP ASAP!! Will give brainliest!
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Hi there! 9.125 * 10^-3 is definitely less than 9.125 * 10^2, because when it comes to negative powers of 10, the numbers are decimals. 10^-3 equals 0.001 or one thousandths in word form. 10^2 is 100. When solving for the answers. 0.009125 is less than 912.5. When 912.5 is divided by 0.009125 912.5 is 100^5 or 100,000 times greater than 0.009125. The answer is that 9.125 * 10^-3 is 100,000 (100^5) times less than 9.125 * 10^2.
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4 years ago
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Find the coordinates of the turning point for the equation of the graph below y=x^2+14x+45
USPshnik [31]

Answer:

(- 7, - 4 )

Step-by-step explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the turning point is

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y = x² + 14x + 45 ← is in standard form

with a = 1, b = 14 , then

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y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4

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4 0
3 years ago
X^2 - 6 x + 9 = 4 root(x^2 - 6 x + 6)​
kkurt [141]
Answer

X1= 3-2 root3 x2= 1 x3=5 x4= 3 +2 root 3
First swap the sides then simplify the equation
Collect like terms
Move all the expression to the left to equal 0
Then collect like terms again
Reorder the terms from ^2 to ^4
Factor the expression
Change the signs
Separate into possible cases
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expeople1 [14]

Answer:

c)The proof writer mentally assumed the conclusion. He wrote "suppose n is an arbitrary integer", but was really thinking "suppose n is an arbitrary integer, and suppose that for this n, there exists an integer k that satisfies n < k < n+2." Under those assumptions, it follows indeed that k must be n + 1, which justifies the word "therefore": but of course assuming the conclusion destroyed the validity of the proof.

Step-by-step explanation:

when we claim something as a hypothesis we can only conclude with therefore at the end of the proof. so assuming the conclusion nulify the proof from the beginning

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