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2 years ago

The diameter of a circle is 10 cm. Find its area in terms of \piπ.

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

7 0

Answer:

I probably need like a picture or example

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A strawberry farm had 7,200 plants in total, one field had 18 rows of 200 plants ; the other field had 9. Rows of

Svetradugi [14.3K]

Answer:

We have a total of 7200 plants.

The plants are distributed in one field with 18 rows of 200 plants and another field with 9 rows of N plants.

Where we want to find the value of N.

The total number of plants in the rows is:

"number of rows times number of plants in each row."

Then the total number of plants is:

18*200 + 9*N

And we know that we have a total of 7200 plants, then:

18*200 + 9*N = 7200

9*N = 7200 - 18*200 = 3600

N = 3600/9 = 400

Then the plants are distributed in 18 rows of 200 plants for one field, and 9 rows of 400 plants in the other field.

8 0

3 years ago

Find the lengths of the sides of the triangle PQR. P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) a. |PQ| = b. |QR| = c. |RP| =

Nat2105 [25]

Given :

Three points , P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .

To Find :

The length of sides .

Given :

We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :

$L=\sqrt{(x-a)^2+(y-b)^2+(z-c)^2}$

Length of PQ :

$PQ=\sqrt{(4-2)^2+(3-1)^2+(4-3)^2}\\\\PQ=\sqrt{4+4+1}=\sqrt{9}\\\\PQ=3$

Length of QR :

$QR=\sqrt{(2-2)^2+(1-7)^2+(3-0)^2}\\\\QR=\sqrt{0+6^2+3^2}\\\\QR=\sqrt{36+9}\\\\QR=\sqrt{45}\\\\QR=3\sqrt{5}$ :

Length of RP :

$RP=\sqrt{(2-4)^2+(7-3)^2+(0-4)^2}\\\\RP=\sqrt{2^2+4^2+4^2}\\\\RP=\sqrt{4+16+16}\\\\RP=\sqrt{36}\\\\RP=6$

Hence , this is the required solution .

4 0

3 years ago

Tell whether x and y show direct variation. Explain your reasoning. y−x=0

Jlenok [28]

Answer:

yes

Step-by-step explanation:

Direct variation is represented as

y = kx, where k is a constant.

We can rewrite y - x = 0 as

y = x (add x to both sides)

This can be looked at as

y = (1)x , so this is a direct variation relationship where k = 1

7 0

3 years ago

The height of the tide over time is shown on the graph. Which of the following equations can be used to reasonably model the dat

Murljashka [212]

Answer:

Option 1. $f(x) = -3sin(\frac{\pi }{6}x)+3$

Step-by-step explanation:

The height of the tide over the time is shown on the graph.

Its a periodic function (sine graph) plotted on a graph in which variables are

Amplitude a = (6-0)/2 = 3

Period = 15-3 = 12

Therefore b = 2π/period = 2π/12 = π/6

horizontal shift = 0

Vertical shift = 3

Since the function starts with negative sign that means its below the x-axis.

So as per standard formula of f(x) = asin(bx+c)+d

option which matches all these parameters is Option 1. $f(x) = -3sin(\frac{\pi }{6}x)+3$

3 0

3 years ago

Read 2 more answers

4) -4y= -x + 4<br> 6) y + 3x = 3

wel

Answer:

x=16/13

y= -9/13

Step-by-step explanation:

A: -4y=-x+4

B: y+3x=3

4B: 4y+12x=12

A+4B: 12x= -x+16

-----> 13x=16

x=16/13

-4y= -16/13+4

4y=16/13-4

y=4/13-1= -9/13

4 0

3 years ago