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2 years ago

The diameter of a circle is 10 cm. Find its area in terms of \piπ.

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

7 0

Answer:

I probably need like a picture or example

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What are the vertex, axis of symmetry, domain and range of the function:

DiKsa [7]

Y=(-x*x)-4x+3
y=-(x^2+4x-3)
4+y=-(x^2+4x+4)+3
y+4=-(x-2)^2.) +3
-4. -4
y=-((x-2)^2)-1

Answers:
Vertex: (2,-1)
AOS:x = 2
Domain: All Real Numbers
Range:[-1,Infinity)

3 0

3 years ago

Monique made several batches of soup for a potluck supper. Each batch required 3\4 0f a pound of potatoes, and she used a total

eimsori [14]

Answer:

$The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.$

$The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).$

Step-by-step explanation:

As given

$Monique\ made\ several\ batches\ of\ soup\ for\ a\ potluck\ supper.$

$Each\ batch\ required\ \frac{3}{4}\ of\ a\ pound\ of\ potatoes.$

$she\ used\ a\ total\ of\ 6 \frac{1}{2}\ pounds\ of\ potatoes.$

As given the expression.

$= \frac{6 \frac{1}{2}}{\frac{3}{4}}$

$= \frac{\frac{13}{2}}{\frac{3}{4}}$

Solving the above

$= \frac{13\times 4}{2\times 3}$

$= \frac{26}{3}$

In the decimal form.

= 8.67 (Approx)

$Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.$

$Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).$

6 0

3 years ago

Suppose your SAT score is 1180. You look up the average SAT scores for

Stella [2.4K]

Answer:

1190

Step-by-step explanation:

3 0

3 years ago

Leslie drank 4/5 pint of juice and Hank drank 7/10 pint of juice. Who drank more

amid [387]

Leslie did. If you multiply 4/5 by two, you get 8/10. 8/10 is greater than 7/10.

5 0

3 years ago

Read 2 more answers

Write a system of equations with the solution (4,-3)

Slav-nsk [51]

Answer:

y = 3x-15 and y = x-7

Step-by-step explanation:

We are asked to write a system of equations with the solution (4,-3)

It is sufficient if we find two lines passing through this point.

Let us take first line as with slope 3.

Then the equation would be of the form

y-y1 = m(x-x1)

y+3 = 3(x-4)

Or y = 3x-15 is one line

Let second line have slope 1

y+3 = 1(x-4)

y = x-7

Now we have two systems of equations as

y = 3x-15 and y = x-7

3 0

4 years ago