Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
The answer to this equation would be k=2
You can use a common denominator and rewrite 3/5 divided by 1/10 as 6/10 divided by 1/10.
Than you can think, “How many ___s are in ___? (Sorry, i don’t know this part)
3/5 divided 1/10 is 6
Answer:
I hope this helps
Step-by-step explanation:
-3 1/8
Answer:
50
Step-by-step explanation:
50 / 10 = 5
5 x 3 = 15
