339/3 = 113, the middle number
average is 113 so 111, 113 and 115
= X -4 you can also use the app Photomath
Answer:
Step-by-step explanation:
Given that 10000 times a fair coin is flipped. Since fair coin prob for head of tail =0.5
If tail comes it will be taken as 1. Hence for the sum to be less than 5000, no of heads <5000
Since trials are large we approximate to normal with mean = np = 5000 and variance = np(1-p) = 2500
Thus no of heads x is normal with (5000, 50)

Since this prob is less than 0.5 only minimum amount to be bet i.e. 1 dollar
If sum of coins <5100, then Z = 
P(Z<2) = 0.9500
This time we can bet maximum of 100 dollars as probability is very high nearer to 1.
Answer:
k = 2
Step-by-step explanation:
Given that x = - 1 is a root of the equation, then it satisfies the equation.
Substitute x = - 1 into the equation and solve for k, that is
3(- 1)² - 2k - 2(- 1) - 1 = 0
3 - 2k + 2 - 1 = 0
- 2k + 4 = 0 ( subtract 4 from both sides )
- 2k = - 4 ( divide both sides by - 2 )
k = 2
Answer:
Step-by-step explanation:
-2 = 0.25p + 0.75p
-2 = 1p
-2/1 = p
-2 = p