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Phoenix [80]
2 years ago
15

HELP! WILL AWARD BRAINLIEST

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
7 0
It should be 580. hope that makes sense:)
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Question on image. <br><br> will report answers out of question. Thank you
olchik [2.2K]

Answer:

84°

Step-by-step explanation:

< DEB = ½× (31+ 137) = ½× (168) = 84°

3 0
3 years ago
If the first 4 terms of an infinite geometric sequence are 150, 120, 96, and 76.8, then the sum of all the terms in the sequence
hammer [34]

The sum of the sequence is 750

<h3>How to determine the sum of the series?</h3>

The series is given as:

150, 120, 96, and 76.8,

Start by calculating the common ratio using:

r = T2/T1

This gives

r = 120/150

r = 0.8

The sum of the series is then calculated as:

S = \frac{a}{1 - r}

This gives

S = \frac{150}{1 - 0.8}

Evaluate

S = 750

Hence, the sum of the sequence is 750

Read more about sequence at:

brainly.com/question/6561461

#SPJ1

4 0
1 year ago
Geometry proof<br> help please
Aleks [24]
JK = MN because of Given

∠JLK = ∠MLN because of the vertical angle theorem

JL = LN because of definition of midpoint

ΔJLK = MLN because of SAS

∠K = ∠N because corresponding angles of congruent triangles are congruent.

Hope this helps!<span />
6 0
2 years ago
Read 2 more answers
The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0
2 years ago
Help! This is due today!
bulgar [2K]

Answer:

27π

Step-by-step explanation:

area of circle = πr^2

= π × 6^2

= 36π

36/4

= 9

36 - 9

= 27π units squared

4 0
2 years ago
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