Answer:
Verified
Step-by-step explanation:
Let A matrix be in the form of
![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
Then det(A) = ad - bc
Matrix A transposed would be in the form of:
![\left[\begin{array}{cc}a&c\\b&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26c%5C%5Cb%26d%5Cend%7Barray%7D%5Cright%5D)
Where we can also calculate its determinant:
det(AT) = ad - bc = det(A)
So the determinant of the nxn matrix is the same as its transposed version for 2x2 matrices
The symbolic representation of the conditional probability

This is a conditional probability problem ; which can be expressed explicitly as ;
- The probability of not being a great hitter Given that the player is an outfielder
- Recall :
Probability of A given B is defined as ;

Let :
Probability that a player is an outfielders = P(O)
Probability that a player is a Great hitter = P(G)
- Probability that a player is not a great hitter = P(G')
- Probability that a player is not a great hitter given that he is an outfielder = P(OnG')
Therefore, we have :

Learn more : brainly.com/question/18153040
You dont tell me which set of numbers so it depends if the first and second in each has a sum greater than the third third is greater than them then it is the answer
Here's how to convert 0.39 to a fraction...
There is not much that can be done to figure out how to write 0.39 as a fraction, except to literally use what the decimal portion of your number, the .39, means.
Since there are 2 digits in 39, the very last digit is the "100th" decimal place.
So we can just say that .39 is the same as 39/100.
So your final answer is: 0.39 can be written as the fraction 39/100 (ALREADY SIMPLIFIED)