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Sonja [21]
2 years ago
12

Help with proofs please

Mathematics
1 answer:
alexandr402 [8]2 years ago
8 0

Answer:

D. Subtraction Property of Equality

Step-by-step explanation:

Hope it helps.

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Help get all this points pls
balandron [24]
It would be b.) y=5x+5
8 0
3 years ago
Read 2 more answers
Reflecting over the x-axis in words and formula
Ksivusya [100]

Answer:

Formula: (x, -y), when reflecting over the x-axis you keep the x-value the same, but change the sign of the y-value. For example: You have the original coordinates (3, 5), and if you reflect it over the x-axis it’ll be (3, -5).

4 0
3 years ago
Please help!! Due really soon!
Alisiya [41]

9514 1404 393

Answer:

  f(x) = 6x +1

Step-by-step explanation:

Differences in x-values (first row) are 1, 1, 1.

Differences in y-values (second row) are 6, 6, 6.

The constant ratio of differences (6/1) tells you the function is linear, and has a slope of m = 6/1 = 6.

Using the first point in the form ...

  y = mx + b

we have ...

  y = 6x + b

  7 = 6·1 + b . . . . (x, y) = (1, 7)

  1 = b . . . . . . subtract 6

Then the equation can be written ...

  y = 6x +1

In functional form, this is ...

  f(x) = 6x +1

4 0
3 years ago
Describe the procedure you<br> performed to derive the slope-intercept form of a linear equation.
defon

Answer:

1. You first have to find the slope

2. Next, you have to find the y-intercept

3. Finally, you have to put it in y = mx + b form.

Step-by-step explanation:

The slope of 2 points is; \frac{y_{2}- y_{1} }{x_{2}-x_{1}}

The y-intercept is; y-y_{1}=m(x-x_{1} )

y = mx + b

m is always the slope

b is always the starting point or y-intercept

6 0
3 years ago
Read 2 more answers
Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the
mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

f(x)=Le^{-Lx}

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

f(x)=e^{-x}

For a)

P(T>2)

P(T>2)=1-P(T\leq 2)

P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx

P(T>2)=1-(-e^{-2}+1)

P(T>2)=e^{-2}=0.1353

For b)

P(T\geq 10/T>9)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

P(T\geq 10/T>9)=P(T\geq 1)

P(T\geq 1)=1-P(T

P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679

4 0
3 years ago
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