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Sonja [21]
2 years ago
12

Help with proofs please

Mathematics
1 answer:
alexandr402 [8]2 years ago
8 0

Answer:

D. Subtraction Property of Equality

Step-by-step explanation:

Hope it helps.

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Compare the difference between an independent event and a dependent event.
pshichka [43]
<h2>⚠ANSWER⚠ </h2>

<em>Dependent event is when two events are dependent events, one event influences the probability of another event whereas independent event has no effect on the probability of another event occurring. </em>

↪DEPENDENT EVENT

When two events are dependent events, one event influences the probability of another event. A dependent event is an event that relies on another event to happen first. Dependent events in probability are no different from dependent events in real life. If you want to attend a concert, it might depend on whether you get overtime at work. if you want to visit family out of the country next month, it depends on whether or not you can get a passport in time. More formally, we say that when two events are dependent, the occurrence of one event influences the probability of another event.

Simple examples of dependent events

  1. Robbing a bank and going to jail.
  2. Not paying your power bill on time and having your power cut off.
  3. Boarding a plane first and finding a good seat.
  4. Parking illegally and getting a parking ticket.

↪INDEPENDENT EVENT

An independent event is an event that has no connection to another event’s chances of happening (or not happening). In other words, the event has no effect on the probability of another event occurring. Independent events in probability are no different from independent events in real life. Where you work has no effect on what color car you drive. Buying a lottery ticket has no effect on having a child with blue eyes.

When two events are independent, one event does not influence the probability of another event.

Simple examples of independent events

  1. Owning a dog and growing your own herb garden.
  2. Paying off your mortgage early and owning a Chevy Cavalier.
  3. Winning the lottery and running out of milk.
  4. Buying a lottery ticket and finding a penny on the floor.

<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>

3 0
2 years ago
Jake has two similar cylindrical pipes. The radius of the first cylindrical pipe is 5 cm. The circumference of the second cylind
Anna11 [10]
V=hpir^2
c=2pir

assuming they havve same height

first one is
v=hpi5^2
v=25hpi

2nd one
c=2pir=20pi
2pir=20pi
2r=20
r=10
v=hpir^2
v=hpi10^2
v=100hpi

big/small=100hpi/25hpir=4

4 times greater
4 0
3 years ago
Tuan is playing a game, but the spinner is incomplete. If the numbers in the sections of the spinner represent the probabilities
ioda

The sum of the numbers should total to 1. Let us say that x is the missing number, therefore:

x + ¼ + ¼ + 1/5 = 1

x = 1 – ¼ - ¼ - 1/5

The numbers should have similar denominator:

x = 20/20 – 5/20 – 5/20 – 4/20

x = 6/20

<span>x = 3/10</span>

8 0
3 years ago
A software company decided to conduct a survey on customer satisfaction. Out of 564 customers who participated in the online sur
nikklg [1K]

Answer:

z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8  

p_v =2*P(z  

Step-by-step explanation:

Information given

n=564 represent the sample selected

X=51 represent the number of people who rated the overall services as poor

\hat p=\frac{51}{564}=0.0904 estimated proportion of people who rated the overall services as poor  

p_o=0.1 is the value to compare

z would represent the statistic

Hypothsis to analyze

We want to analyze if the proportion of customers who would rate the overall car rental services as poor is 0.1, so then the system of hypothesis are:  

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

The statistic for a one z test for a proportion is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8  

And the p value since we have a bilateral test is given b:

p_v =2*P(z  

3 0
3 years ago
X+ 2y=3 and x=5 in y=mx+b form​
lesya692 [45]
I don’t know how to solve those type of problems sorry
6 0
3 years ago
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