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gulaghasi [49]
2 years ago
8

The ratio of peter's height to albertina's height is 147cm what is peter's height​

Mathematics
1 answer:
stellarik [79]2 years ago
8 0

Answer:

4'9.87

Step-by-step explanation:

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Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin
Artemon [7]
"<span>Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find \bar{d}, s_{d}, the t-test statistic, and the critical values to test the claim that \mu_{d} = 0"

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find </span><span>\bar{d}
You are asked to find the mean difference between the two variables, which is given by the formula:
\bar{d} =  \frac{\sum (x - y)}{n}

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example: 
</span><span>\bar{d} =  \frac{6}{8} = 0.75</span>

B) Find <span>s_{d}
</span><span>You are asked to find the standard deviation, which is given by the formula:
</span>s_{d} =  \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }

These are the steps to follow:
1) Subtract the mean difference from each pair's difference 
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
s_{d} = \sqrt{ \frac{101.5}{8-1} }
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
t =  \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}

where SE = standard error is given by the formula:
SE =  \frac{ s_{d} }{ \sqrt{n} }

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract  \mu_{d}
6) divide by the standard error

In our example:
SE = 3.81 / √8
      = 1.346

The problem gives us <span>\mu_{d} = 0, therefore:
t = [(9.75 - 9) - 0] / 1.346</span>
  = 0.56

D) Find t_{\alpha / 2}
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find <span>t_{\alpha / 2} = 1.895</span>

Since our t-value is less than <span>t_{\alpha / 2}</span> we can reject our null hypothesis!!

7 0
3 years ago
I need help in this question for math. 1/2x10
Alex17521 [72]
You can just put the 10 over 1 and multiply across. Then simplify! Hope this helps (:

8 0
2 years ago
Amanda and jamie are standing 25 feet apart and spot a bird in the sky between them the angle of elevation from Amanda is 25 fee
finlep [7]

Answer:

25.2294 feet

Step-by-step explanation:

We can solve this question drawing a triangle using the values given and then using the law of sines. (See image attached to know how to draw the triangle and use the values).

First we need to find the third angle of the triangle, that is, the angle in the vertix where the bird is:

y + 55 + 63 = 180

y = 62°

The relation between the angles and the distances are:

25 / sin(y) = x / sin(63)

25 / 0.8829 = x / 0.8910

x = 25 * 0.8910 / 0.8829 = 25.2294 feet

4 0
3 years ago
For party decorations, you buy 6 rolls of crepe paper and 20 balloons for $11.90. After you start decorating, you determine that
Morgarella [4.7K]

Answer:

Find out the  how much did each roll of crepe paper cost .

To prove

Let us assume that the cost of the  roll of crepe paper be x.

Let us assume that the cost of the balloon be y .

As given

For party decorations, you buy 6 rolls of crepe paper and 20 balloons for $11.90.

Than the equation becomes

6x + 20y = 11.90

As given

After you start decorating, you determine that you need more party decorations.

You buy 2 more rolls of crepe paper and 15 more balloons for $6.05.

Than the equation becomes

2x + 15y = 6.05

Than two equations are

6x + 20y = 11.90 and 2x + 15y = 6.05

Multiply 2x + 15y = 6.05 by 3 and subracted with 6x + 20y = 11.90

6x - 6x + 45y -20y = 18.15 - 11.90

25y = 6.25

y = \frac{6.25}{25}

y = $0.25

Put in the equation 2x + 15y = 6.05

2x + 15 × 0.25 = 6.05

2x = 6.05 - 3.75

2x = 2.3

x = \frac{2.3}{2}

x = $1.15

Therefore the each roll of crepe paper cost is  $1.15 .

6 0
3 years ago
Read 2 more answers
Approximate the area under the curve over the specified interval by using the indicated number of subintervals (or rectangles) a
RideAnS [48]

Split up [1, 3] into 4 subintervals:

[1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

each with length (3 - 1)/2 = 1/2.

The right endpoints r_i are {3/2, 2, 5/2, 3}, which we can index by the sequence

r_i=1+\dfrac i2

with 1\le i\le4.

Evaluating the function at the right endpoints gives the sampling points f(r_i), {27/4, 5, 11/4, 0}.

Then the area is approximated by

\displaystyle\int_1^3f(x)\,\mathrm dx\approx\frac12\sum_{i=1}^4f(r_i)=\frac12\left(\frac{27}4+5+\frac{11}4+0\right)=\boxed{\frac{29}4}

5 0
2 years ago
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