The object compresses the spring up to 0.8577m.
<h3>What is Potential Energy?</h3>
Potential Energy is the energy possessed by an object at rest.
The object is falling from the rest and it is assumed that the friction on the ramp is zero and the air resistance is also considered to be zero so only the gravitational force acts and the total potential energy gets converted to Kinetic Energy.
The total amount of potential energy at the top of the ramp is given by
Ep=mgh
Ep=3 * 9.81 *5
Ep=147.15 Joules
This is equal to kinetic energy.
From the formula for elastic potential energy
The distance up to which the spring is compressed is determined
The force constant = 400N/m
147.15 =(1/2)k(x²)
294.3=(400)(x²)
0.73575=x²
x=0.8577 m
So, the object compresses the spring up to 0.8577m.
- When the object compresses the spring, the potential energy of the spring is converted into Kinetic Energy so it will push the object back again.
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Answer:
m = 7
Step-by-step explanation:
2m + -4 = 10
Reorder the terms:
-4 + 2m = 10
Solving
-4 + 2m = 10
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '4' to each side of the equation.
-4 + 4 + 2m = 10 + 4
Combine like terms: -4 + 4 = 0
0 + 2m = 10 + 4
2m = 10 + 4
Combine like terms: 10 + 4 = 14
2m = 14
Divide each side by '2'.
m = 7
Simplifying
m = 7
2:3 and 4:6 are two different ratios that are equivalent to 2/3.
B)
Answer:
Step-by-step explanation:
Given:
Area = 3x^3 - 16x^2 + 31x - 20
Base:
x^3 - 5x
Area of trapezoid, S = 1/2 × (A + B) × h
Using long division,
(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x
= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh
= 2S/Bh - A/B
= (2S/B × 1/h) - A/B
Since, x^3 - 5x = B
Comparing the above,
A = 32x^2 - 92x + 40
2S/B = 6
Therefore, h = 1
Answer:
the answer is 4
Step-by-step explanation:
81 minus 28 minus 2 minus 11 equal 40 28 divide 7 is 4
