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2 years ago

Can the sides of a triangle have lengths 2, 10, and 11? yes no

Mathematics

1 answer:

madreJ [45]2 years ago

4 0

Answer:

Yes

Step-by-step explanation:

Triangle inequality theorem states that a triangle can exist if

a + b > c; a + c > b; b + c > a

a = 2; b = 10; c = 11

2 + 10 = 12; 12 > 11.

2 + 11 = 13; 13 > 10.

10 + 11 = 21; 21 > 2.

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What is 2 2/3 - 1 1/3? answer using backslash for example 2/3

Rudik [331]

Answer:

-1

Step-by-step explanation:

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3 years ago

At the 6th grade school dance, there are 132 boys, 89 girls and 14 adults.

S_A_V [24]

Answer:

132:189 and

132 to 89

Step-by-step explanation:

I'm pretty sure

3 0

2 years ago

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

3 0

3 years ago

What is the product of 4 × 40?

nignag [31]

Answer:

160 Hope this helps :)

8 0

3 years ago

Read 2 more answers

Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.

Serggg [28]

Same here, we do a quick switcharoo on the variables first,

$\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5
\\\\\\
x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y$

6 0

3 years ago