Answer:
a = 102.05
b = 393.76
B = 93°
Step-by-step explanation:
The law of sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
Since the sum of angles in a triangle is 180°, angle B must be ...
B = 180° -72° -15° = 93°
and the unknown sides must be ...
a = c/sin(C)·sin(A) = 375·sin(15°)/sin(72°) ≈ 102.05192
B = 93°
b = 375·sin(93°)/sin(72°) ≈ 393.75796
_____
The rounding requirement got cut out of your picture, so we can't help you with that.
Answer:
x = 4√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
Leg <em>a</em> = 8
Leg <em>b</em> = 4
Hypotenuse <em>c</em> = <em>x</em>
<em />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [Pythagorean Theorem]: 8² + 4² = x²
- Evaluate exponents: 64 + 16 = x²
- Add: 80 = x²
- [Equality Property] Square root both sides: √80 = x
- Rewrite: x = √80
- Simplify: x = 4√5
Answer:
The answer is
Step-by-step explanation:
C. f(x) = 500(2)^x
2020
Answer:
I would say try D and then try A
Step-by-step explanation:
Answer:
And if we solve for a we got
Step-by-step explanation:
Let X the random variable that represent the lenght time it takes to find a parking space at 9AM of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
As we can see on the figure attached the z value that satisfy the condition with 0.7 of the area on the left and 0.3 of the area on the right it's z=0.524
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got