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frosja888 [35]
3 years ago
10

PLEASE HELP?! Explain how to do these types of problems fast!!

Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

m∠J = m∠Z = 46°

Step-by-step explanation:

m∠J = m∠Z = 46°

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A student saves $3 dollars on August 1, $5 on August 2, $7 on August 3, and so on. How much will she save in August 20 ?
Delvig [45]
Here is your answer

Money saved on each successive day is-

$3, &5, $7....

Clearly it forms an AP,

where

a1= 3

common difference, d= 2

n=20

So,

using formula

Tn= a1+(n-1)d

T20= 3+(20-1)2

= 3+ 19×2

= 3+ 38

=41

So, money saved on August 20= $41

Sum of money saved upto August 20 =
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
= $440

HOPE IT IS USEFUL
5 0
3 years ago
Read 2 more answers
if a taxi charges $3.50 for the first on-fifth of a mile, then $0.55 cents for each additional one-fifth mile, how far can one t
34kurt
Let's forget for the tie being the cost ($3.5)of the 1st fifth of a mile:

Taxi charge excluding $3.5, is $13.95 - $3.5 = $10.45.

If each of the 5th (1/5) of a mile costs $0.55, then with $10.45 we can drive:
10.45/0.55 = 19 fifth of a mile. Add to that the 1st fifth = 20 fifth of a mile
 20 fifth = 20 x 1/5 = 4 miles (answer)

7 0
3 years ago
Katherine baked a round cake that is 9 inches in diameter. She wants to decorate the cake by putting a piece of ribbon around th
kaheart [24]

Answer:

28.26 inches long of ribbon

5 0
3 years ago
Read 2 more answers
NEED HELP ASAP !! WILL MARK BRAINLEAST<br> SHOW WORK TOO !!!
irinina [24]

Step-by-step explanation:

(1 +  \cos(x) )(1 -  \cos(x) )

1  -  \cos {}^{2} (x)

=  \sin {}^{2} (x)

b.

\frac{1}{ \cot {}^{2} (x) }  -  \frac{1}{ \cos {}^{2} (x) }

\frac{1}{ \frac{ \cos {}^{2} (x) }{ \sin { }^{2} (x) } }  -  \frac{1}{ \cos {}^{2} (x) }

\frac{1}{ \cot {}^{2} (x) }  -  \frac{   \csc {}^{2} (x)   {} }{ \cot {}^{2} (x) }

\frac{ -  \cot {}^{2} (x) }{ \cot {}^{2} (x) }

- 1

c.

\sec {}^{2} ( \frac{\pi}{2} - x ) )( \sin {}^{2} (x)  -  \sin {}^{4} (x))

( \csc {}^{2} (x) )( \sin {}^{2} (x)  -  \sin {}^{4} (x  )

\csc {}^{2} (x) ( \frac{1}{ \csc {}^{2} (x) }  -  \frac{1}{  \csc {}^{4}  (x) } )

1 -  \frac{1}{ \csc {}^{2} (x) }

1 -  \sin {}^{2} (x)

\cos {}^{2} (x)

3 0
2 years ago
Find the standard deviation of the following data. Round your answer to one decimal place. x 0 1 2 3 4 5 P(X
lbvjy [14]

Answer:

<em></em>\sigma = 1.8<em></em>

<em></em>

Step-by-step explanation:

Given

\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}

Required

The standard deviation

First, calculate the expected value E(x)

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5  * 0.2

E(x) = 2.7

Next, calculate E(x^2)

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2  * 0.2

E(x^2) = 10.5

The standard deviation is:

\sigma = \sqrt{E(x^2) - (E(x))^2}

\sigma = \sqrt{10.5 - 2.7^2}

\sigma = \sqrt{10.5 - 7.29}

\sigma = \sqrt{3.21}

<em></em>\sigma = 1.8<em> --- approximated</em>

5 0
3 years ago
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