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djyliett [7]
2 years ago
12

Terica is dissolving a substance in a solution for a chemistry experiment. Terica measured the amount of substance remains in gr

ams over time passed in seconds. The linear relationship is shown on the graph. Find the average rate of change of the grams remaining between x=3 and x=6.
Mathematics
1 answer:
vfiekz [6]2 years ago
7 0

Answer: -1 1/3

She asked me where I was from

I said "Somewhere you never been to"

Little town outside of Knoxville

Hidden by some dogwood trees

She tried talkin' with my accent

We held hands and waded into

That blue water

She left her flip-flops by my Red Wings on the beach

[Chorus]

Yeah but, now I'm dodging potholes in my sunburnt Silverado

Like a heart-broke Desperado, headin' right back to my roots

Somethin' 'bout the way she kissed mе tells me she'd lovе Eastern Tennessee

Yeah, but all I brought back with me was some sand in my boots

[Verse 2]

I said "Let's go shoot tequila"

So we walked back to that beach bar

She said "Don't cowboys drink whiskey?" (huh)

So we drank bottom shelf

She said ", that sky looks perfect"

I said "Girl, you've never seen stars like the ones back home"

And she said "Maybe I should, see 'em for myself"

[Chorus]

Yeah, but now I'm dodging potholes in my sunburnt Silverado

Like a heart-broke Desperado, headin' right back to my roots

Somethin' 'bout the way she kissed me tells me she'd love Eastern Tennessee

Yeah, but all I brought back with me was some sand in my boots

[Bridge]

I said meet me in the mornin'

And she told me I was crazy

Yeah, but I still thought that maybe she'd show up

[Chorus]

Oh, but now I'm dodging potholes in my sunburnt Silverado

Like a heart-broke Desperado, headin' right back to my roots

Somethin' 'bout the way she kissed me tells me she'd love Eastern Tennessee

Yeah, but all I brought back with me was some sand in my boots

Yeah, but all I brought back with me was some sand in my boots

Step-by-step explanation:

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What is the equation of the graphed line written in standard form?
Masja [62]

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To find the slope of the line you could either use the two points on the line or just look and see.

Start from the point farther down, the point on (5,0). Look and see how many units it takes to go up/down to where the point on (0,3) is.

If it goes up, then you are at a positive slope so far. If it goes down, then you are at a negative slope so far. It takes 3 units UP (positive) to go onto the line that (0,3) is on.

Now see how far does it take to go left/right to where the point on (0,3) is. If you have to go left, that means you have a negative; if it goes right then you have a positive. It takes 5 units LEFT (negative) to where (0,3) is.

A positive (up) and a negative (left) make a negative, so your slope is how many units it took to go vertically/how many units it took to go horizontally.

Your slope is -3/5.

Now to solve for b, or the y-intercept, you can look on the graph to see where the point lies on the y-axis (vertical). The point lies on 3 on the y-axis, so your y-intercept is 3.

Since you have the slope and can see the y-intercept of the graphed line, you can make the equation y = mx+b by plugging in -3/5 for the slope and plugging in 3 for b (y-intercept).

y = (-3/5)x+(3)

Remove the parentheses: y = -3/5x+3.

Now to convert from slope-intercept form into standard form, you will have to move everything to the left side and leave only b, or 3.

Add -3/5x to both sides.

3/5x+y = 3

You can't have a fraction in standard form, so multiply everything in the equation by 5.

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Answer is:

C. 3x+5y = 15

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3 years ago
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levacccp [35]

Answer:

x = 9

Step-by-step explanation:

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130 +(6x-4)=180

6x-4=180-130

6x-4=50

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cricket20 [7]
C= 6.7

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