You can tell a cell is the active cell when it has a

Write a program that prompts the user to enter two positive integers less than 1,000,000,000 and the program outputs the sum of

alexira [117]

Answer:

In Python:

low = int(input("Low: "))

high = int(input("High: "))

if low >= 1000000000 or high >=1000000000:

print("Out of range")

else:

mylist = []

for num in range(low,high+1):

flag = False

if num > 1:

for i in range(2, num):

if (num % i) == 0:

flag = True

break

if not flag:

mylist.append(num)

print(num, end = " ")

print()

print("The twin primes are: ",end="")

count = 0

for i in range(1,len(mylist)):

if mylist[i] - mylist[i-1] == 2:

print(str(mylist[i])+" & "+str(mylist[i-1]),end=", ")

count+=1

print()

print("There are "+str(count)+" twin primes")

Explanation:

See attachment for complete program where comments were used to explain each line

Download txt

7 0

3 years ago

you need to configure a wireless network using wpa2-enterprise. which of the following components should be part of your design?

Iteru [2.4K]

Answer: AES encryption

802.1x

Explanation:

4 0

2 years ago

n a poll, 6767% of Internet users are more careful about personal information when using a public Wi-Fi hotspot. What is the

a_sh-v [17]

Answer:

The probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.964

If the survey subjects <em>volunteered</em> to respond , then those with the strongest opinions are most likely respond. The survey sample is then not randomly selected, the survey may have a <em>response bias.</em>

Explanation:

Let P(at least one is more careful about personal information when using a public Wi-Fi hotspot) denote the probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot, then we have the equation

P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot)

If 67% of Internet users are more careful about personal information when using a public Wi-Fi, then 33% of them are not.

P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot) = $0.33^{3}$ ≈ 0.036

P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - 0.036 = 0.964

4 0

3 years ago

Please try and solve this

Genrish500 [490]

Answer:

Many students coming into Woodworking 108 are bewildered by “all those little marks ... Parts of an inch will be referred to in fraction form instead of its decimal equivalent. ... on divisions of 2: 1” 2= ½”. ½” 2= ¼”. ¼” 2= 1/8”. 1/8” 2= 1/16”. 1/16” 2= 1/32” ... way is to realize there are 16/16 in an inch and count back 3 of the 1/16 ...

Explanation:

4 0

4 years ago

A file named 'input.txt' contains a list of words. Write a program that reads the content of the file one word at a time. Check

Margarita [4]

Answer:

// here is code in java.

import java.io.*;

import java.util.Scanner;

class Main{

// function to check a word is palindrome or not

private static boolean is_Palind(String str1)

{

// if length of String is 0 or 1

if(str1.length() == 0 || str1.length() == 1)

{

return true;

}

else

{

// recursively check the word is palindrome or not

if(str1.charAt(0) == str1.charAt(str1.length()-1))

{

return is_Palind(str1.substring(1,str1.length()-1));

}

else

{

return false;

}

// driver function

public static void main(String[] args)

{// variable to store word

String word;

// BufferedWriter object

BufferedWriter buff_w = null;

// FileWriter object

FileWriter file_w = null;

// Scanner object

Scanner sc = null;

try

{

// read the input file name

sc = new Scanner(new File("input.txt"));

// output file

file_w = new FileWriter("output.txt");

// create a buffer in output file

buff_w = new BufferedWriter(file_w);

// read each word of input file

while(sc.hasNext())

{

word = sc.next();

// check word is palindrome or not

if(is_Palind(word))

{

// if word is palindrome then write it in the output file

buff_w.write(word);

buff_w.write("\n");

}

// close the buffer

buff_w.close();

// close the input file

sc.close();

}

// if there is any file missing

catch (FileNotFoundException e) {

System.out.println("not able to read file:");

}

// catch other Exception

catch (IOException e) {

e.printStackTrace();

}

Explanation:

Create a scanner class object to read the word from "input.txt" file.Read a word from input file and check if it is palindrome or not with the help of is_Palind() function.it will recursively check whether string is palindrome or not. If it is palindrome then it will written in the output.txt file with the help of BufferedWriter object. This will continue for all the word of input file.

Input.txt

hello world madam

level welcome

rotor redder

output.txt

madam

level

rotor

redder

3 0

3 years ago