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natita [175]
3 years ago
11

If f(x) = 3x 7, find f(a - 1) a. 3a 6 b. 3a 4 c. 3a 8 d. 3a 10

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0
Hello,

Let's suppose f(x)=3x+7
f(a-1)=3(a-1)+7=3a-3+7=3x+4
Answer B with a sign "++++++++++++++++++++++++++++"


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Plase dont awnser just for points
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So 3 2/3 is about 3.67 so it would go in between 3.65 and 3.7. So it would be the second answer.
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3 years ago
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Name the transformations of the next equation y=3(x+6) - 5
klemol [59]

Answer:

vertical stretch

Step-by-step explanation:

8 0
2 years ago
Roberto wants to display his 18 sports cards in an album . Some pages hold 2 cards and others hold 3 cards .
nexus9112 [7]

Answer:

Step-by-step explanation:

Assuming Roberto wants to completely fill each page that he puts cards in, this function describes the number of 2-card pages, a, and 3-card pages, b.

2a + 3b =18

Ricardo can fill up 9 2-card pages, and 6 3-card pages.

a=9, b=0

We must add 2 3-card pages at a time,so that we have an even number for the 2-card pages:

a=6, b=2

Add 2 to b once more:

a=3, b=4

One more time:

a=0, b=6:

Thus, Ricardo can display his figures in the following page combinations:

a=9, b=0

a=6, b=2

a=3, b=4

a=0, b=6

Remember that a= number of 2-card pages and b=number of 3-card pages

There are 4 different ways that Ricardo can arrange his figures in terms of what kind of pages he uses. 

3 0
3 years ago
a school held a tennis tournament. after each round one fourth of the players were eliminated. if there were 64 players at the s
Sveta_85 [38]

Answer:

If there are 32 teams in the tournament and 1 winner, there were 31 games. So, 63 - 31 = 32 games.

 

8 0
2 years ago
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A triangle has a perimeter of 90 centimeters write and use a linear system
lawyer [7]

We are given sides of the triangle by expression

First side : n

Second side : m = 5n-5.

Third side : l = 5/4 m - n.

Perimeter is 90.

Therefore, first equation could be set :

n +m +l = 90   --------------equation(1)

Second equation would be

m = 5n-5        --------------equation(2)

Third equation would be

l = 5/4 m - n   --------------equation(3)

Let us solve the system of equations by substitution.

Substituting m = 5n-5 and l = 5/4 m - n in first equation.

We get

n +5n-5 +5/4 m - n= 90

Now, substituting m = 5n-5 in above equation we get

n +5n-5 +5/4 (5n-5) - n= 90

5n + 25n/4 -5 - 25/4 =90

5n + 6.25n -5-6.25 = 90.

11.25n-11.25 = 90

Adding 11.25 on both sides, we get

11.25n-11.25+11.25 = 90+11.25

11.25n = 101.25.

Dividing both sides by 11.25, we get

n=9.

Plugging n=9 in 2nd equation.

m = 5(9)-5 = 45 -5 = 40.

Plugging n=9 and m=40 in first equation, we get

9 +40 +l = 90

49 +l = 90.

Subtracting 49 from both sides, we get

49-49 +l = 90-49

l = 41.

Therefore, sides are of lengths l = 41, m= 40 and n=9.


5 0
3 years ago
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