Answer:
75/4 = 18.75
Step-by-step explanation:
Because a squar is 4 sides add 75 is the perimiter
<h3>Answer:</h3>
Equation of the ellipse = 3x² + 5y² = 32
<h3>Step-by-step explanation:</h3>
<h2>Given:</h2>
- The centre of the ellipse is at the origin and the X axis is the major axis
- It passes through the points (-3, 1) and (2, -2)
<h2>To Find:</h2>
- The equation of the ellipse
<h2>Solution:</h2>
The equation of an ellipse is given by,
Given that the ellipse passes through the point (-3, 1)
Hence,
Cross multiplying we get,
- 9b² + a² = 1 ²× a²b²
- a²b² = 9b² + a²
Multiply by 4 on both sides,
- 4a²b² = 36b² + 4a²------(1)
Also by given the ellipse passes through the point (2, -2)
Substituting this,
Cross multiply,
- 4b² + 4a² = 1 × a²b²
- a²b² = 4b² + 4a²-------(2)
Subtracting equations 2 and 1,
- 3a²b² = 32b²
- 3a² = 32
- a² = 32/3----(3)
Substituting in 2,
- 32/3 × b² = 4b² + 4 × 32/3
- 32/3 b² = 4b² + 128/3
- 32/3 b² = (12b² + 128)/3
- 32b² = 12b² + 128
- 20b² = 128
- b² = 128/20 = 32/5
Substituting the values in the equation for ellipse,
Multiplying whole equation by 32 we get,
3x² + 5y² = 32
<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
Answer:
The answer is below
Step-by-step explanation:
An equation shows the relationship between two or more variables. An equation is a statement that shows the equality between expressions. An equation with infinitely many solution is when all numbers are solutions, that is there is no one solution. Example is: x + 3 = x + 3.
When each side of an equation has been simplified, equations that have the same coefficients and the same constants on each side have infinitely many solutions
Answer:
(9-j)-3
Step-by-step explanation:
Let's start from the beginning and subtract j from 9. Because the word "from" is used, 9 will be the first number and j will be the second number.
We have 9-j
Now, we have to subtract 3 from the final answer. So, we have (9-j)-3
Answer:
<h3>25%</h3>
Step-by-step explanation:
Total number of student in the school = 152 students
Number of student that have more than one pet = 38
percentage of the students have more than one pet will be expressed as
% of student with more than 1 pet = number of student with more than one pet/total number of student * 100%
% of student with more than 1 pet = 38/152 * 100
% of student with more than 1 pet = 3800/152
% of student with more than 1 pet = 25%
Hence 25% of the students in the school have more than one pet.
