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earnstyle [38]
3 years ago
10

Simplify the expression :) pls help

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

c^6 d^18 x^3..........

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emmainna [20.7K]
Buy what he said to multiple or divide length times width
5 0
3 years ago
What number must be added to both sides of the equation to complete the square?
adelina 88 [10]
(x-8)²= x²-16x+64
x²-16x+8=0
Therefore 56 must be added.

Good luck
7 0
3 years ago
Critical points of x+5/x+2>0
Scorpion4ik [409]

Answer:

{-5, -2}

Step-by-step explanation:

In a case like this please use parentheses to remove ambiguities.  If I were to take your "x+5/x+2" literally, I'd have to write x             plus 5/x           plus 2.

I suspect that you actually meant (x + 5) / (x + 2), and will start with that.

First of all, this function is not defined at x = -5 or at x = -2.  Thus, -5 and -2 are critical points.  

Secondly, there may be one or more critical points beyond this.  To find out, we have to differentiate (x+5)/(x+2):

           (x + 2)(1) - (x + 5)(1)

f '(x) = ------------------------------

                  (x + 2)

Here it's clear that x cannot = -2, which would cause division by zero.

Thus, our critical values are {-5, -2}.

8 0
3 years ago
Identify the congruent angles in the figure. Explain your reasoning.
cupoosta [38]

Answer:

Step-by-step explanation:

<CBD is congruent to <ABE by Vertical Angles

<ABC is congruent to <DBE by Vertical Angles

6 0
3 years ago
36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence
tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, \pi = \frac{36}{60} = 0.6

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

7 0
3 years ago
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