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zheka24 [161]
3 years ago
15

Find the equation of a line parallel to 2x-3y=9 that passes through the point (1, -3)

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer:

<u>y = 2/3x - 11/3</u>

Step-by-step explanation:

2x-3y=9

Rearrange to find the parallel gradient:

-3y = -2x+9

y = 2/3x -3

M(gradient) = 2/3

M(parallel gradient) = 2/3

Substitute the gradient and the points point A and B into the equation :

y-b = m(x-a)

y - (-3) = 2/3(x-1)

3y + 9 = 2x -2

3y = 2x -11

<u>y = 2/3x - 11/3</u>

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