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sveta [45]
2 years ago
10

Is the system of equations consistent and independent, consistent and dependent, or inconsistent? y=−3x 12y=−6x 2 Select the cor

rect answer from the drop-down menu. Choose.
Mathematics
1 answer:
tresset_1 [31]2 years ago
8 0

System of equations helps to compare two real-life situations. The system is an Independent Consistent System.

<h3>What is a System of the equation?</h3>

Inconsistent System

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

Given to us

y = −3x + 12

y = −6x + 2

As we have the value of y in both equations equate it against each other,

-3x + 12 = -6x + 2\\\\-3x + 6x = 2 -12\\\\3x = -10\\\\x  = \dfrac{-10}{3}

We know the value of x, substitute the value of x in the equation of y,

y = -6x + 2\\\\y = -6(\dfrac{-10}{3}) + 2\\\\y = +20 + 2\\\\y = 22

As the value of both x and y is unique, therefore, there is a unique solution for the given system of equations.

Thus, the system has a unique solution, therefore, the system is an Independent Consistent System.

Learn more about System of equation:

brainly.com/question/12895249

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What is the value of f(x) = –x^2 – 2 when x = –1?
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Answer:

-1

Step-by-step explanation:

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f(x) = -1

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Answer:

Option c is correct that is Home health aides.

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6 0
3 years ago
The cubic polynomial below has a double root at r4 and one root at x = 6 and passes Through the point (2, 36) as shown. Algebrai
qaws [65]

The graph in the question is missing.

Answer:

y  = \frac{-1}{4}( x^3 + 2x^2 - 32x -96)

Step-by-step explanation:

The function is cubic

It has roots as -4, -4 , 6

this means the value of x = -4, -4 , 6 which makes the entire equation zero

so we have solutions as

x+4 = 0

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on forming a cubic equation using these

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put x = 2

(2+4)(2+4)(2-6) = (6)*(6)*(-4)

which exceeds 36 so we product the equation with -1/4 to get 36

Final equation

y = \frac{-1}{4} (x+4)(x+4)(x-6)

  y  = \frac{-1}{4}( x^3 + 2x^2 - 32x -96)

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