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Levart [38]
3 years ago
9

Which of the following is the correct point-slope equation for the line that passes through the point (-4,-2) and is parallel to

the line given by y=5x+44?

Mathematics
2 answers:
SVEN [57.7K]3 years ago
8 0

Answer:

D

Step-by-step explanation:

drek231 [11]3 years ago
8 0

Answer:

Step-by-step explanation:

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What is the value of the expression below? 8 + 24 / 2 X 6 - 4
umka21 [38]

8 + 24 / 2 X 6 - 4

following order of operations divide 24 by 2:

8 + 12 x 6 -4

Multiply 12 by 6:

8 + 72 -4

Add 8 and 72:

80-4

Subtract to get 76

6 0
3 years ago
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Find the surface area of the composite figure.
taurus [48]

Answer:

surface area is 39

Step-by-step explanation:

add the areas of each geometric figure making up the composite 3D figure.

first 3D figure

2+2+6+6

=16---eq 1

from third 3D figure

4+4+10+5

= 23

from 1 and 2

16+23

= 39

may be!! I'm not sure bout this answer

3 0
3 years ago
I POSTED THIS QUESTION THREE TIMES IF YOU ANSWER THIS (CORRECTLY) GO ANSWER MY OTHER QUESTIONS JUST TO GET THE POINTS YOU DONT H
Charra [1.4K]

Answer:

12/3=4

Y= Time and X=The number of shoelaces

6 0
3 years ago
Read 2 more answers
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
2 years ago
Help please (inequalities)
zaharov [31]

Answer:

The First one is the answer

4 0
2 years ago
Read 2 more answers
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