A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
It depends on what level of classes you take, but algebra classes in college do tend to be harder than algebra classes in high school or middle school.
7(10 visits) ≤ 68
70 ≤ 68
Not Viable
7(9 visits) ≤ 68
63 ≤ 68
Viable
The first solution is not viable because 10 visits will give a total cost of $70 per month, which is $2 over his monthly budget of $68.
The second solution is viable. He could visit the gym a maximum of 9 times per month for a total of $63 a month and that will be under his $68 monthly budget.
Hope this helps! :)
Answer:
-7
Step-by-step explanation:
-20 × -7 = 140
140 × -7 = -980
