Answer:
I think it's 4.89897948557
Step-by-step explanation:
The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
35x + 15
Step-by-step explanation:
5x(7 + 3)
35x + 15
Answer:
k = 10
Explanation:
The initial polynomial is:
If f(-2) = 0, then when we replace x by -2, the result will be 0. It means that we can write the following equation:
Therefore, we can solve for k as follows:
So, the value of k is 10
Answer:
3
Step-by-step explanation:
- 4x³y² + 6
the x is raised to the power of 3 , that is exponent of x is 3
