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r-ruslan [8.4K]
3 years ago
11

There are 418 students at a school. Han estimates that they each drink about 5 glasses of water each day.

Mathematics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

Step-by-step explanation:

a) together, they all drink about 2,090 glasses of water in one day. (418 * 5 = 2,090).

b) 2,090 * 7 (7 days in 1 week) = They drink about 14,630 glasses of water in one week.

c) 14,630 * 4 (4 weeks in 1 month) = About 58,520 glasses of water in one month.

d) 1,000,000/58,520 ≈ 17. It would take all of the students about 17 months to drink 1,000,000 glasses of water.

Hope that helps!

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Lyrx [107]

Answer:

x=1/4 , y=-1/4. You can confirm this by substituting the numbers in.

Step-by-step explanation:

4 0
3 years ago
Divide 120 in the ratio of 1:2
mestny [16]

Answer:

40:80

Step-by-step explanation:

x+2x=3x

3x=120

120/3=

40

40*2=80

40:80=1:2

6 0
4 years ago
What is a simplest way to find out x
konstantin123 [22]

Answer:

You should start with a simple equation. And remember- practice makes perfect.

The basic algebraic equation involves simple addition or subtraction with one unknown quantity, such as 2 + x = 7.

1.  Subtract 2 from both sides: 2 - 2 + x = 7 - 2.

2. Simplify the equation by doing the math: 2-2+x=7-2=0+x=5, or x = 5.

3. Check your work by substituting the answer, 5, into the equation for x.

The correct answer is x=5.




5 0
3 years ago
Read 2 more answers
What is the algebraic expression in 11x-6x-x
adelina 88 [10]

Answer:

4x

Step-by-step explanation:

Simplify. Combine like terms. Note that x = 1x, being that there is one variable of x.

11x - 6x = 5x

5x - x = 4x

4x is your answer.

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5 0
3 years ago
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The marketing director of a large department store wants to estimate the average number of customers who enter the store every f
Dahasolnce [82]

Answer:

36.5674\leq x'\leq61.4326

Step-by-step explanation:

If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:

x-t_{\alpha /2}\frac{s}{\sqrt{n} } \leq x'\leq x-t_{\alpha /2}\frac{s}{\sqrt{n} }

where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, \alpha is equal to 0.05 (it is calculated as: 1 - 0.95) and  t_{\alpha /2} is the t value with n-1 degrees of freedom that let a probability of \alpha/2 on the right tail.

So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and t_{\alpha /2} by 2.2621 we get:

49-2.2621\frac{17.38}{\sqrt{10} } \leq x'\leq 49+2.2621\frac{17.38}{\sqrt{10} }\\49-12.4326\leq x'\leq 49+12.4326\\36.5674\leq x'\leq61.4326

Finally, the interval values that she get is:

36.5674\leq x'\leq61.4326

8 0
3 years ago
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