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3 years ago

What is a simplest way to find out x

2 answers:

katrin2010 [14]3 years ago

8 0

To find the x-intercept of a given linear equation, plug in 0 for 'y' and solve for 'x'. To find the y-intercept, plug 0 in for 'x' and solve for 'y'. In this tutorial, you'll see how to find the x-intercept and the y-intercept for a given linear equation. Check it out!

konstantin123 [22]3 years ago

5 0

Answer:

You should start with a simple equation. And remember- practice makes perfect.

The basic algebraic equation involves simple addition or subtraction with one unknown quantity, such as 2 + x = 7.

1. Subtract 2 from both sides: 2 - 2 + x = 7 - 2.

2. Simplify the equation by doing the math: 2-2+x=7-2=0+x=5, or x = 5.

3. Check your work by substituting the answer, 5, into the equation for x.

The correct answer is x=5.

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Write an equation of the line that has a slope of -5 and a y- intercept of 4 in a slope intercept form.

Anastasy [175]

Answer:

y=-5x+4

Step-by-step explanation:

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3 years ago

Which two values of x satisfy the equation square root 3-2cos x = 2?

Andrei [34K]

Answer: x=2π/3 and x=4π/3

Step-by-step explanation:

The equation we have is $\sqrt{3-2cosx} =2$ . All we have to do is get cosine alone to find the 2 values of x.

$3-2cosx=4\\-2cosx=1\\cosx=-\frac{1}{2}$

Now that we have our cosine left, we can use our unit circle to figure out when does cosx=-1/2. Cosine is the x value of the coordinate.

x=2π/3

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2 years ago

Please help 100 points

muminat

Answer:

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Step-by-step explanation:

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2 years ago

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Help there are five people at the carnival they are 15 people at the other carnival how many people are there

faltersainse [42]

I think there are 20 people

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3 years ago

Find each absolute value | 4+2i | | 5-i | | -3i |

galina1969 [7]

How to get answer for number 1: | 4+2i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}$

How to get answer for number 2: | 5-i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}$

Number 3 how to get answer: | -3i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3$

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3 years ago

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