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serg [7]
3 years ago
7

What is the answer to this division equation?

Mathematics
2 answers:
tatyana61 [14]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

43/8 = 5 + 3/8 = 5.375

Option B seems to be the closest rounded answer.

zvonat [6]3 years ago
7 0
What's up? it's B!

8 x 5 is 40, and that is the highest you can get if we are doing remainders. so, the remainder would be 3, the final answer would be 5 r. 3

best of luck with your studies!
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What is the nineteenth term in the sequence 7, 10, 13, 16,...? A 64 B 61 C 57 D 19
Over [174]

Answer:

B. 61

Step-by-step explanation:

7, 10, 13, 16...

ok so were starting with 7 and adding 3 every time

im going to do 3 times 19 like as if we started with 3 then im going to add 4

3 x 19 = 57

57 + 4 = 61

the 19th term is 61

8 0
4 years ago
Read 2 more answers
CAN U GUYS PLZ HELP!!
attashe74 [19]

Answer:

C. 5/2

Step-by-step explanation:

Two points that the graph passes through are (-5, -4) and (-3, 1). This tells us that the graph goes up 5 units at the same rate that it goes right 2 units. Since the slope of a graph is simply the movement of the y values over the movement of the x values, the slope of this graph is 5/2, which is option C.

6 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
4 years ago
Pls answer this with a picture showing the correct box plot
faust18 [17]

Answer/Step-by-step explanation:

To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.

Given, {2, 3, 5, 6, 10, 14, 15},

Minimum value = 2

Median = middle data point = 6

Q1 = 3 (the middle value of the lower part of the data set before the median)

Q3 = 14 (middle value of the upper part of the data set after the median)

Maximum value = 15

If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.

See the attachment below for the correct box plot.

3 0
3 years ago
I need help doing thsi
Naily [24]
True! Because T is the defining letter of the line, so it would be true!

Hope this helps!! :)
7 0
4 years ago
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