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Morgarella [4.7K]
2 years ago
7

A spinner has 9 equal sections labeled A, B, C, D, E, F, G, H, and I. What is P(not A)? 89 23 13 19

Mathematics
1 answer:
VMariaS [17]2 years ago
4 0

Answer:

P(not A) = 8/9

Step-by-step explanation:

To write a simple probability, write a fraction. The bottom is all the possibilities, here there are 9. So put a 9 on the bottom. Then on top write how many ways the event can happen. There are 8 ways you can land on "Not A" (that is: B, C, D, E, F, G, H, I) So 8 goes on top. Simplify if possible. 8/9 cannot be simplified.

P(not A) = 8/9

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Kamal invested $1200 in a savings acc paying 1.8% per yr compound interest.
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3. Make a class frequency table using 2 rule of the following data. Find the Mean and make a Cumulative frequency Histogram [10]
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Answer:  Mean = 284

Step-by-step explanation:

<u>Data:</u>

125, 126, 127, 127, 137

201, 202, 207, 211, 215, 218, 224, 237, 261

301, 308, 310, 315, 330, 330, 360, 380, 393, 394

401, 401, 410, 421, 422, 424

<u>Class Frequency Table:</u>

\boxed{\begin{array}{c|c|c}\underline{\text{Intervals}}&\underline{\text{\qquad Frequency\qquad}}&\underline{\text{Cumulative Frequency}}\\0-49&0&0\\50-99&0&0\\100-149&5&5\\150-199&0&5\\200-249&8&13\\250-299&1&14\\300-349&6&20\\350-399&4&24\\400-449&6&30\\450-499&0&30\end{array}}\\.\qquad \qquad \qquad \qquad \quad \ 30                                                                    

<u>Mean:</u>

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8518/30 = 283.933

<u>Cumulative Frequency Histogram:</u>

Create the graph based on the Interval and Cumulative Frequency of the class frequency table above. <em>(see image)</em>

<em />

<em />

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