You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Answer:
2/5
Step-by-step explanation:
36 divided by 90 is 2/5.
When solving for X you do the opposite to a number if you are moving it to the other side of the problem. so, since x is being divided by 4/9, 4/9 would be multiplied to the opposite or to the 9/10.
Answer:
Marci answered 40 out of 50
Marci answered 2 more questions correctly.
Step-by-step explanation:
Donovan got 38 out of 50
Marci got 80% which means 40 out of 50
40-38 = 2
Answer:
θ ≈ 71.6°
Step-by-step explanation:
The angle between two lines with slopes m₁ and m₂ is:
tan θ = | (m₂ − m₁) / (1 + m₁m₂) |
Here, m₁ = -2 and m₂ = 1.
tan θ = | (1 − (-2)) / (1 + (-2)(1)) |
tan θ = | 3 / -1 |
tan θ = 3
θ ≈ 71.6°
