Consider the graph for Question #4. This represents the temperature change over a period of time on a single day.

Mathematics

1 answer:

evablogger [386]2 years ago

8 0

Answer:

I think its degrees an hour and im almost posotive :D

Step-by-step explanation:

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Question 3<br> Find the equation of the line joining (-2,4) and (3,7)

otez555 [7]

Answer:

y = (3/5)x+26/5 or 5y = 3x+26

Step-by-step explanation:

Applying,

The equation of a line in two point form

(y₂-y₁)/(x₂-x₁) = (y-y₁)/(x-x₁)............... Equation 1

From the question,

Given: y₂ = 7, y₁ = 4, x₂ = 3, x₁ = -2

Substitute these values into equation 1

(7-4)/[3-(-2)] = (y-4)/(x+2)

3/5 = (y-4)/(x+2)

5(y-4) = 3(x+2)

5y-20 = 3x+6

5y = 3x+6+20

5y = 3x+26

y = (3/5)x+26/5

Hence the equation of the line is y = (3/5)x+26/5 or 5y = 3x+26

7 0

2 years ago

alexandrea and imani each think of a number. alexandras number is 8 more than Imanis number. the sum of two numbers is 50. what

juin [17]

Alexandera=a
imani=i

a is 8 more than i or
a=8+i

the sum of the 2 numbers is 50 or
a+i=50

a=8+i
so subsitute 8+i for a in a+i=50
8+i+i=50
8+2i=50
subtract 8 from both sides
2i=42
divide both sides by 2
i=21

subsiutte into a=8+i

a=8+21
a=29

a=29
i=21

3 0

2 years ago

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. Sixteen seconds pass from the time

lisov135 [29]

Answer:

See attached for a graph

Step-by-step explanation:

We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.

The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...

(x, y) = (0, -8)

The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.

The second point you will put into your sine tool is ...

(x, y) = (8, -3)