The flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
Given, f = x³i + y³j + z³k
we have to find the flux of the given function f = x³i + y³j + z³k
On partial differentiating the function, we get
f' = 3x²i + 3y²j + 3z²k
f' = 3(x²i + y²j + z²k)
So, the flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
Hence, the flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
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Answer:
-16 + 8z
Step-by-step explanation:
4(-4 + 2z)=
Distribute the 4
4*-4 + 4(2z)
-16 + 8z
Answer:
3,375 mph is the anwser I'm 95% surw
Answer:
True
Step-by-step explanation:
The size of the vertex cover is atleast twice the size of the maximum edge. Vertex must contain atleast one vertex from the matched edge. Vertex are never the strong dual solutions of each other.
Its a solution. There is no way that you can solve it if it is an equation.
