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ale4655 [162]
2 years ago
6

A construction crew needs to pave a road that is 202 miles long. The crew paves 8 miles of the road each day. The length, L (in

miles), that is left to be paved after d days is given by the following function.
L(d)= 202-8d
Answer the following questions.
a) How many miles of the road does the crew have left to pave after 13 days?
___miles
b) If 138 miles of the road is left to be paved, how many days has the crew been paving the road?
___days
Mathematics
2 answers:
nasty-shy [4]2 years ago
8 0

Answer:

A)98.  B)8

Step-by-step explanation:

A) 8x13=104

202-104=98

B)202-138=64

64/8=8

the crew has been paving the road for 8 days.

Hope this helps.

san4es73 [151]2 years ago
7 0

Answer:

A) 98 miles

B) 8 days

Step-by-step explanation:

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mafiozo [28]

Answer:

D.

Step-by-step explanation:

The formula is Sum(n) = (n -2) 180.

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3 years ago
The figure below shows the design of a truss to support the weight of a roof. In this truss design, ∠A⩭∠D and ĀF⩭DF.
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Answer:

m\angle A= 30^{\circ}

Step-by-step explanation:

In the question, we're given \angle A\cong \angle D. Therefore, the measure of these two angles must be equal.

To find the value of x, set these two angles equal to each other:

4x-26=x+16

Add 26 and subtract x from both sides:

3x=42

Divide both sides by 3:

x=\frac{42}{3}=14

Since \angle A was labelled as 4x-26, substitute x=14 to find its measure:

\angle A=4(14)-26,\\\angle A=56-26,\\\angle A=\boxed{30^{\circ}}

You can also substitute x=14 into the label of angle D as angle A is congruent to angle D for easier calculations (14+16=\boxed{30^{\circ}}).

5 0
3 years ago
What is the greatest common factor of 90xy3 and 12xy?
Dovator [93]
The greatest common factor is 6xy
3 0
3 years ago
What is the answer for this problem
neonofarm [45]
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5 0
3 years ago
Determine which of the following equations have the same solution set by recognizing properties rather than solving.
Pepsi [2]

Answer

a) 2 x + 3 = 13 - 5 x

   7 x = 13 -3

   7 x = 10

      x = \dfrac{10}{7}

b) 6 + 4 x = 10 x + 26

     6 x = 20

        x = \dfrac{20}{6}

        x = \dfrac{10}{3}

c) 6 x + 9 = 13/5 - x

    7 x = \dfrac{13}{5} -9

       x = \dfrac{-32}{35}

d) 0.6 + 0.4 x = x + 2.6

         0.6 x = -2

        x = \dfrac{-20}{6}

        x = \dfrac{-10}{3}

e) 3(2x + 3) = 13/5 -x

   6 x + 9 = 13/5 - x

    7 x = \dfrac{13}{5} -9

       x = \dfrac{-32}{35}

f) 4 x = -10 x + 20

      14 x = 20

          x = \dfrac{20}{14}

          x = \dfrac{10}{7}

g) 15(2x + 3) = 13 - 5x

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         35 x = -32

       x = \dfrac{-32}{35}

h)15(2x + 3) + 97 = 110 - 5x

   30 x + 45 + 97 = 110 - 5x

    35 x = -32

   x = \dfrac{-32}{35}

so , the solution of part c, e, g, h is same which is x = \dfrac{-32}{35}

      the solution of part a, f  is same which is x = \dfrac{10}{7}

   

     

3 0
3 years ago
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