All categories

2 years ago

Pls help! Show work! How many points do you want

Mathematics

1 answer:

Rom4ik [11]2 years ago

3 0

Answer:

She must score 90 points

Step-by-step explanation:

Find the average of the first 2 tests

76 + 80 = 156

Divide the sum of the first 2 tests by how many tests there were

156 ÷ 2 = 78

Multiply 82 by 3

82 x 3 = 246

Subtract 156 from 246

246 - 156 = 90

Add all the numbers together to get the average

90 + 80 + 76 = 246

246 ÷ 3 = 82

Hope this helps!

You might be interested in

Write 4x2 = 12 in standard form.

AlekseyPX

Answer: 4x²−12

Step-by-step explanation:

mark as brainliest hope this helps

7 0

3 years ago

Read 2 more answers

Find the equation of the line through point (5,1) and perpendicular to 5x−y=−3.

Elanso [62]

Answer:

you will need to specify a scale and draw the line from which I will solve with simultaneous linear equations

3 0

3 years ago

Read 2 more answers

Someone please do this and show work

tatiyna

Answer:

1) 1/4

2) 3/5

Step-by-step explanation:

1) The rate of change is basically the slope, and you can find the slope by doing:

change in y/change in x

I started with the point (0,-2) because it's on the line

It goes up 1 and left 4 to get to the second point on the line

So change in y/change in x = 1/4 (this is the rate of change)

2) This is basically the same thing, but you need to do some subtraction.

Change in y = -9-(-3) = -6

Change in x = -5 - 5 = -10

Change in y/change in x = 3/5 (this is the slope or rate of change)

7 0

3 years ago

A gumball machine contains 300 grape flavored balls, 400 cherry flavored balls, and 500 lemon flavored balls. What is the probab

Svet_ta [14]

Answer:

Pr(of getting 1grape ball, 1 cherry ball and 1 lemon ball) =0.20832

Step-by-step explanation:

Let the grape falvored ball be represented by G,

Cherry flavored balls be C

Lemon flavored balls be L

the possible order of picks for getting 1grape ball, 1 cherry ball and 1lemon ball are; GCL or GLC or CGL or CLG or LGC or LCG

Pr(of getting 1grape ball, 1 cherry ball and 1 lemon ball)

= Pr(GCL) or Pr(GLC) or Pr(CGL) or Pr(CLG) or Pr(LGC) or Pr(LCG)

with replacement we have;

Probability = $\frac{number of required outcomes}{number of possible outcomes}$

= $\frac{300}{1200}*\frac{400}{1200}*\frac{500}{1200} +\frac{300}{1200}*\frac{500}{1200}*\frac{400}{1200} +\frac{400}{1200}*\frac{300}{1200}*\frac{500}{1200} \\ \\+\frac{400}{1200}*\frac{500}{1200}*\frac{300}{1200} +\frac{500}{1200}*\frac{300}{1200}*\frac{400}{1200} +\frac{500}{1200}*\frac{400}{1200}*\frac{300}{1200}$

= 0.03472 + 0.03472 +0.03472 + 0.03472 + 0.03472 + 0.03472

=0.20832

3 0

3 years ago

It’s on the picture .

Marrrta [24]

Answer:

slope 2

yint 1

equation y=2x+1

3 0

3 years ago