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Lana71 [14]
2 years ago
13

I don’t know if the answer i put is correct,, can someone help me?

Mathematics
1 answer:
joja [24]2 years ago
5 0
R=60pi/(2pi) (second one)
The circumference of an arbitrary circle is 2*pi*r, where r is the radius, so we can set the equation up like so, based on the info given:
2*pi*r=60*pi
r=60pi/(2pi)
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Which correctly completes this number sentence?
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Answer:

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The length of a rectangle is 5m less than three times the width, and the area of the rectangle is 50m^(2). Find the dimensions o
Ilia_Sergeevich [38]

Answer:

The width is 5m and the length is 10m.

Step-by-step explanation:

Rectangle:

Has two dimensions: Width(w) and length(l).

It's area is:

A = w*l

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This means that l = 3w - 5

The area of the rectangle is 50m^(2)

This means that A = 50. So

A = w*l

50 = w*(3w - 5)

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

3w^{2} - 5w - 50 = 0

So

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\bigtriangleup = (-5)^{2} - 4*3*(-50) = 625

w_{1} = \frac{-(-5) + \sqrt{625}}{2*3} = 5

w_{2} = \frac{-(-5) - \sqrt{625}}{2*3} = -3.33

Dimension must be positive result, so

The width is 5m(in meters because the area is in square meters).

Length:

l = 3w - 5 = 3*5 - 5 = 10

The length is 10 meters

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Mekhanik [1.2K]

Answer:

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Step-by-step explanation:

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