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melamori03 [73]
2 years ago
7

Rút gọn bthuc 7x(4y-x) + 4y(y-7x) - (4y^2 -7x)

Mathematics
1 answer:
ale4655 [162]2 years ago
3 0

¢✓¢==¢=

Step-by-step explanation:

==`==¢=¢✓%✓™€✓✓€=€✓€✓

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Please help guys this is just domain and range
STatiana [176]

Answer:

Domain: (0,3)

Range: (0,1)

Step-by-step explanation:

Domain is the interval of the x-axis of the graphed function

Range is the interval of the y-axis of the graphed function

5 0
2 years ago
Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
Blizzard [7]

Answer:

The answer is

y = 3

y =  - 4

Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

\frac{6}{y + 1}  \times  \frac{y - 2}{y - 2}  +  \frac{y}{y - 2}  \times  \frac{y + 1}{y + 1}

Which equals

\frac{6y - 12}{(y -2) (y + 1)}  +  \frac{ {y}^{2} + y }{(y - 2)(y + 1)}

Add the fractions

\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

\frac{6y}{(y + 1)(y - 2)}  =  \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}

Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

6 0
2 years ago
Read 2 more answers
What frequency does 125/232 represent
dedylja [7]
Uh thinking itz -66/100
6 0
3 years ago
Read 2 more answers
Question 8<br> What is (4x - 5)(6x + 5) expressed as a trinomial?
erica [24]

Answer:

24x^2 -10x - 25

Step-by-step explanation:

24x^2 + 20x - 30x - 25

24^2 -10x - 25

8 0
2 years ago
Read 2 more answers
40 points” help HLP HL
cestrela7 [59]

Answer:

D: {(-5, -4, 2, 2, 5)}

R: {(-6, 3, 4, 1, 5)}

The relation is NOT a function.

Step-by-step explanation:

By definition:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components  (range/output/y value).

Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).

Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.

8 0
2 years ago
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