Question

-8-8x^2=-31 how to solve for x

Answer 1

Answer:

x = ± $\sqrt{\frac{23}{2\sqrt{2}}}$

Step-by-step explanation:

-8 - 8x^2= -31

Since this is a quadratic, it needs to be factored.

First, move the x to the other side:

-8 = 8x^2 - 31

Then, get the x alone by first adding 31:

23 = 8x^2

then dividing by 8:

x^2 = 23/8

Finally, square root both sides and remember the even roots property:

x = ± $\sqrt{\frac{23}{8}}$

and simplify the root 8:

x = ±  $\sqrt{\frac{23}{2\sqrt{2}}}$

Note: This answer may have a mistake.