A 2kg box is pushed from rest across a horizontal surface where friction between the box and the surface is negligible. Students

Question

3 years ago

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A 2kg box is pushed from rest across a horizontal surface where friction between the box and the surface is negligible. Students

record the applied force at several equally spaced positions while pushing the box and create the graph shown. The change in momentum of the box is most nearly.

SAT

1 answer:

ivolga24 [154] · Answer 1 · 2023-01-19T02:19:38+03:00

The momentum of an object is a measure of force that acts on the object for a given time

Using the assumed final velocity, the change in momentum is 40 kgm/s

<h3>How to calculate the change in momentum</h3>

The change in momentum of an object is calculated using:

$\Delta p =m\Delta v$

Where:

m represents the mass of the object
$\Delta v$ represents the change in velocity of the object

From the question, the mass of the box is 2 kg, and the box starts from rest.

This means that, the initial velocity is 0 m/s

The final velocity is not given. So, we make use of the following assumed value for the final velocity

v = 20 m/s

The equation then becomes

$\Delta p =m\Delta v$

$\Delta p = m(v - u)$

Substitute known values

$\Delta p = 2(20 - 0)$

$\Delta p = 40$

Hence, the change in momentum is 40 kgm/s