Answer:
The coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.
Step-by-step explanation:
Since the varsity soccer team has 20 players, and three of the players are trained to be goalies while the remaining 17 can play any position, and only 11 players can be on the field at once, and the coach wants to make sure there is exactly one goalie on the field, to determine how many ways can the coach choose a lineup of 11 players if exactly 1 player must be a goalie the following calculation has to be made:
3 x 17 ^ 10 = X
3 x 2,015,993,900,449 = X
6,047,981,701,347 = X
Therefore, the coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.
(i just changed my answer)
sqrt is the square root of
v=sqrt(2(ke)/m)
The x-intercept and y-intercept are (-3,0) and (0,4/5).
Given,
-3x-4=-5y-8
We need to find the intercept of the line.
<h3>What are intercepts?</h3>
Intercepts are the points at which the line crosses the axis.
There are two intercepts :
x-intercept - the point at which the line crosses the x-axis.
Here, y = 0.
y-intercept - the point at which the line crosses the y-axis.
Here, x = 0.
The line is -3x - 4 = 5y - 8
Put x = 0,
-3 x 0 - 4 = 5y - 8
0 - 4 = 5y - 8
5y = 8 - 4
y = 4 / 5
So,
( 0, 4/5 ) is the point where the line crosses the y-axis.
This is the y-intercept.
Put y = 0,
-3x - 4 = 5y - 8
-3x - 4 = 5 x 0 - 8
-3x - 4 = 0 - 8
-3x - 4 = 8
3x = -8 - 4
3x = -12
x = -12/4
x = -3
( -3, 0 ) is the point where the line crosses the x-axis.
This is the x-intercept.
Thus x-intercept and y-intercept are (-3,0) and (0,4/5).
Learn more about intercept here:
brainly.com/question/14180189
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