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crimeas [40]
2 years ago
10

What is the slope of the line that passes through (-4,2) and (6,-8)

Mathematics
1 answer:
Naddik [55]2 years ago
3 0

Answer:

y = x + -2

Step-by-step explanation:

I know you're probably asleep but here's the answer. And I'm 14 years old, so I might be young and undereducated.

(-4,2) and (6,-8)

-8-2 = -10

6 -(-4) = 10 (-10/10 = -1)

-8 = 6(-1) + b

-8 = -6 + b

-2 = b

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Please help.. I will give points
Daniel [21]

A. 8^9/2= around 11585.2375; (sqrt8)^9= around 11585.2375. So choice A shows a pair of equivalent expressions.

B. (3sqrt125)^9=1,953,125; 125^9/3=1,953,125. So choice B also shows a pair of equivalent expressions.

C. 12^2/7= around 2.03394; (sqrt12)^7= around 5,985.96759. So choice C does not show a pair of equivalent expressions.

D. 4^1/5=around 1.31951; (sqrt4)^5=32. So choice D also doesn't show a pair of equivalent expressions.

Your answers are A and B.

I hope this helps ;)

4 0
3 years ago
Read 2 more answers
What two numbers make on thousand
Igoryamba

Answer:

500 and 500

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
​ A sample of n = 9 college students is used to evaluate the effectiveness of a new Study Skills Workshop. Each student’s grade
forsale [732]

Answer:

B) μD = 0.60 ± 0.10(1.397)

Step-by-step explanation:

The confidence interval is given by:

MD±t_{\alpha/2, n-1} \frac{s}{\sqrt{n} }

Where

MD=60

n=9

df=n-1=8

t_{\alpha/2, n-1}=1.397

s=\sqrt{0.09} =0.3

Then the confidence interval is

μD=0.60±1.397*(0.3/√9)

μD=0.60±0.10*(1.397)

6 0
3 years ago
a closed circular water tank in a subdivision is made up of concreate aluminum. its outer diameter is 8.4 m and its height is 12
m_a_m_a [10]

Answer:

122.7792 sq. m

Step-by-step explanation:

diameter= 8.4 m

therefore, radius = r = 4.2 m.......( as radius is 1/2 of diameter)

height = h= 12 m

only the exterior is to painted so the total surface area of the cylinder is taken,

total surface area of cylinder = 2π r( h+r)

=2* 3.14* 4.2*(12+4.2)

=122.7792 sq. m

5 0
3 years ago
Find the lengths of the sides of the triangle PQR. P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) a. |PQ| = b. |QR| = c. |RP| =
Nat2105 [25]

Given :

Three points ,  P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .

To Find :

The length of sides .

Given :

We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :

L=\sqrt{(x-a)^2+(y-b)^2+(z-c)^2}

Length of PQ :

PQ=\sqrt{(4-2)^2+(3-1)^2+(4-3)^2}\\\\PQ=\sqrt{4+4+1}=\sqrt{9}\\\\PQ=3

Length of QR :

QR=\sqrt{(2-2)^2+(1-7)^2+(3-0)^2}\\\\QR=\sqrt{0+6^2+3^2}\\\\QR=\sqrt{36+9}\\\\QR=\sqrt{45}\\\\QR=3\sqrt{5} :

Length of RP :

RP=\sqrt{(2-4)^2+(7-3)^2+(0-4)^2}\\\\RP=\sqrt{2^2+4^2+4^2}\\\\RP=\sqrt{4+16+16}\\\\RP=\sqrt{36}\\\\RP=6

Hence , this is the required solution .

4 0
3 years ago
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