Answer:
the snow could go with Iowa and the other 3 can be with Washington
The answer for your question is Monitor
Answer:
a. Ed/eD
b. RF=0.12
Explanation:
The alleles for genes D/d and E/e are:
- D_: only on neck spikes
- dd: along back spikes
- E_: long spikes
- ee: short spikes
After testcrossing a double heterozygote (DdEe x ddee) there are 4 types of offspring, two of them much more abundant than the other two. The homozygous recessive parent can only produce <em>ed</em> gametes, so the phenotypes of the offspring depend on the gametes that the double heterozygous parent produced.
The offspring was:
- Ed/ed 79
- ed/ed 12
- ED/ed 10
- eD/ed 76
Total: 177
a) This result suggests that the genes are linked. Since recombination is a rare event, the most abundant phenotypes always come from the parental gametes, and the least abundant come from the recombinant gametes.
<u>Therefore, the genotype of the doube heterozygote parent was </u><u><em>Ed/eD</em></u><u>.</u>
b) Recombination frequency (RF) = Recombinants / Total
RF = (12+10)/177
<u>RF = 0.12</u>
a point mutation only mutates and changes that particular spot in the DNA strand while a frameshift changes the whole strand by moving the bases either one forward or backward