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1 year ago

What is the distance between the points (7,5) and (4,9)

Mathematics

2 answers:

katrin2010 [14]1 year ago

7 0

Answer:

Step-by-step explanation:

marissa [1.9K]1 year ago

6 0

Using the distance formula, the answer is 5

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If you measure 5/6 meter how many twelfths have you measured

Alinara [238K]

1/6 = 2/12 because 12 is 2 times 6.
Multiply both numbers by 2 to get your answer:
5/6 = 10/12

4 0

2 years ago

Solve the system of linear equation 8X plus 5Y equals 18 and 6X plus Y equals -2 by using the linear Combination method Emmaus d

Hunter-Best [27]

$\text{The solution is } x = \frac{-14}{11} \text{ and } y = \frac{62}{11}$

Solution:

Given system of equations are:

8x + 5y = 18 ------- eqn 1

6x + y = -2 -------- eqn 2

Multiply eqn 2 by -5

-30x -5y = 10 ----- eqn 3

Add eqn 1 and eqn 3 so that y terms gets eliminated

8x + 5y = 18

-30x -5y = 10

( + ) --------------

-22x = 28

Divide both sides by -22

$x = \frac{28}{-22}\\\\x = \frac{-14}{11}$

Substitute the x value in eqn 1

$8(\frac{-14}{11}) + 5y = 18\\\\\frac{-112}{11} + 5y = 18\\\\5y = 18 + \frac{112}{11}\\\\5y = \frac{310}{11}\\\\y = \frac{62}{11}$

$\text{Thus the solution is } x = \frac{-14}{11} \text{ and } y = \frac{62}{11}$

8 0

2 years ago

Plz awnser i have ixl and ive already crack my screen so help no explanation just awnsrr

rjkz [21]

The answer is 6c=2.75 hope this helps

3 0

3 years ago

1. A professional basketball used for league play has a diameter of 25 cm. Which of the following is closest to the volume of th

yKpoI14uk [10]

Answer:

V = 8,181.23 $cm^{3}$

Step-by-step explanation:

Unfortunately, we are not given any answer choices to choose from but using the information provided we can find the actual volume of the basketball. A basketball is made in the shape of a sphere and the formula for the volume of a sphere is the following...

V = $\frac{4}{3} * \pi * r^{3}$

radius of a circle/sphere is half of it's diameter. Since we are provided the diameter size we simply divide it by 2 which would give us 12.5cm. Now we simply plug this value into the formula and solve for V.

V = $\frac{4}{3} * \pi * 12.5^{3}$