integer userInput
integer i
integer mid
integer array(20) number
userInput = 1
for i = 0; userInput >= 0; i = i + 1
if number[i] > -1
userInput = Get next input
number[i] = userInput
i = i - 1
mid = i / 2
if i > 9
Put "Too many inputs" to output
elseif i % 2 == 0
Put number[mid - 1] to output
else
Put number[mid] to output
The first computer is the Eniac which was 50 tons!
Answer:
import java.util.Scanner;
public class num2 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count =0;
int total = 0;
System.out.println("Enter the numbers");
int num = in.nextInt();
while(num!=-1){
total = total+num;
count++;
System.out.println("Enter the next number");
num = in.nextInt();
}
//Compute the average
double average = (double) total/count;
//Outputs
System.out.println("Total count of numbers entered "+(count));
System.out.println("Sum of the numbers "+total);
System.out.printf("Average is %.2f ",average);
}
}
Explanation:
- Using java programming language
- Import scanner class to receive user input
- declare variables count and total and initialize to zero
- Prompt user to enter numbers
- Use a while statement with the condition while(num!=-1)
- Within the while body keep prompting user to enter a number, increase count and update total
- when -1 is entered the loop breaks and average is calculated
- Use printf() method to print average to 2 decimal places.
When right clicking an object in word, Shortcut menu appears which contains frequently use commands that relate to the object
