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marissa [1.9K]
2 years ago
13

A town has a population of 13000 and grows at 2.5% every year. What will be the population after 5 years, to the nearest whole n

umber?
Mathematics
2 answers:
vova2212 [387]2 years ago
5 0

Answer:

The population will be 14708

Step-by-step explanation:

formula

A = P (1+r)^t

Initial population = P = 13000

Growth rate = r = 2.5% = 0.025

Number of years = t  = 5 years.

A = 13000 (1+.025)^5  = 14708

brainly.com/question/12498268

ki77a [65]2 years ago
3 0

Answer:

helloo ur answer is 14708

Step-by-step explanation:

Initial population = P = 13000

Growth rate = r = 2.5% = 0.025

Number of years = t  = 5 years.

The population after 5 years is given by:
a=p(1=r)
q=13000(1+0.025^5)
which is equal to

14708 uwu
give brainlest if u want

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3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
I need help like quick plssss
Vera_Pavlovna [14]

Answer:

172.8

Step-by-step explanation:

24+18+5+3=50

360/50=7.2

7.2x24=172.8

4 0
3 years ago
Read 2 more answers
PLZ HELP
Irina-Kira [14]

Answer:

Step-by-step explanation:

8 0
3 years ago
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