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3 years ago

Team A scored 6 points. Team B scored 42 points. Write the ratio of Team A's score to

Mathematics

2 answers:

goblinko [34]3 years ago

3 0

Not sure if it’s correct.. 6:42 is the ratio

Vaselesa [24]3 years ago

3 0

6:42 is the ratio!! I calculated

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3 years ago

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4 years ago

How many ways are there to rearrange the letters ALIVE in such a way that the word EVIL is not contained in the resulting word

Sergio [31]

Answer: 118 combinations.

Step-by-step explanation:

In ALIVE we have 5 letters, rearranging it we have the possible options of:

5 options for the first letter.

4 options for the second letter, as one was already chosen for the first one

3 options for the third letter, as 2 were already chosen.

2 options for the fourth letter.

1 option for the last letter.

The total number of combinations will be equal to the product of the numbers of options for each letter, then we have:

5*4*3*2*1 = 120 combinations.

And the combinations where the word EVIL is formed are:

AEVIL

EVILA

2 combinations, then the total number of combinations such that the word evil is not formed are:

120 - 2 = 118 combinations.

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3 years ago

(GEOMETRY HELP PLS) What is the approximate measure of angle F? Use the law of sines to find the answer.

spayn [35]

You can just use sine.

Sin(F) = opposite/hypotenuse = 28/40.

F = $sin^{-1}$ (28/40)

Plug into your calculator.

44.4

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3 years ago

Read 2 more answers

a rectangle has a height of n3+4n2+3n and a width of n^3+5n^2 express the area of the entire rectangle

alukav5142 [94]

<u>Given</u>:

It is given that the height of the rectangle is $n^3+4n^2+3n$

The width of the rectangle is $n^3+5n^2$

We need to determine the area of the entire rectangle.

<u>Area of the rectangle:</u>

The area of the rectangle can be determined using the formula,

$A=height \times width$

Substituting the values, we have;

$A=(n^3+4n^2+3n)(n^3+5n^2)$

Multiplying each term within the parenthesis, we get;

$A=n^{3} n^{3}+n^{3} \cdot 5 n^{2}+4 n^{2} n^{3}+4 n^{2} \cdot 5 n^{2}+3 n n^{3}+3 n \cdot 5 n^{2}$

Simplifying, we get;

$A=n^{6}+5 n^{5}+4n^{5}+20 n^{4}+3 n^{4}+15 n^{3}$

Adding the like terms, we have;

$A=n^{6}+9n^{5}+23 n^{4}+15 n^{3}$

Thus, the area of the entire rectangle is $n^{6}+9 n^{5}+23 n^{4}+15 n^{3}$

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4 years ago