You will need this formula:
Years = ln (Total / Principal) / rate
(where "ln" means natural logarithm)
and we'll use $100 and $200 for beginning and ending amount
Years = ln (200 / 100) / rate
Years = 0.69314718056 / .052
Years =
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13.3297534723
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Rounding to the nearest tenth of a year:
Years =
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13.3
Source:
http://www.1728.org/rate2.htm
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We are given: On january 1, 2000 initial population = 67,255.
Number of people increase each year = 2935 people.
Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.
Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).
So, we can setup an equation as
Total population after t years = Number of t years * rate of increase of population + fix given population.
In terms of function it can be written as
P(t) = t * 2935 + 67255.
Therefore, final function would be
P(t) = 2935t +67255.
So, the correct option is d.P(t) = 67255 + 2935t.
Answer:
Step-by-step explanation:
area of rectangle=length*width
=17 cm*9 cm
=1323 cm^2
perimeter of rectangle=2(l+w)
=2(17+9)
=2*26
=52 cm
area of square=l^2
=12^2
=144 m^2
perimeter of sqaure=4l
=4*12
=48 m
Step-by-step explanation:
The given equations are :
-x+6y = 16 ...(1)
8x-6y = -2 ...(2)
The y-variable will be eliminated when adding the system of equations.
Adding equations (1) and (2).
-x+6y+8x-6y = 16+(-2)
7x = 14
x = 2
Put the value of x in equation (1).
-2+6y = 16
6y = 16+2
y = 3
There is only one solution to the system of equations i.e. (2,3).