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Lynna [10]
2 years ago
8

Please help with this ques​

Mathematics
1 answer:
Mumz [18]2 years ago
7 0

Answer:

quadrants |||

quadrants ||

quadran |

quadrants |v

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Addison is 3 years younger than Nathan. Write a algebraic expression. plz help
AnnZ [28]

Answer:

A = N - 3

Step-by-step explanation:

A = Addison

N = Nathan

Addison is 3 years younger than Nathan.

A = N - 3

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A liter is equal to 100 centimeters . Is a centiliter a greater measure than a milliliter?
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No a milliliter is the same amount as a centimeter
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Find the height of a parallelogram with the base of 9.44 meters and an area of 70.8 square meters
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Area = base x height

70.8 = 9.44 x height

height = 70.8 ÷ 9.44 = 7.5 m

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Ryan bought 36 cupcakes at the bakery.He was given an additional 8 cupcakes for being a
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8 boxes

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What is the equation of the rational function g(x) and its corresponding slant asymptote?
bija089 [108]

The solution to the Questions are

  • The alternate hypothesis demonstrates that there are two possible outcomes for the test.
  • Decision rule: If z > 2.05 or z<-2.05, reject H0
  • z=2.59
  • The two-tailed nature of the test is shown by the alternative hypothesis.
  • The result of the test yields the following P-value: 0.0096

<h3>What is the alternate hypothesis?</h3>

(a)

The alternate hypothesis demonstrates that there are two possible outcomes for the test.

(b)

Here we have

n_{1}=40,\\\\ \bar{x}_{1}=102,\sigma_{1}=5,n_{2}=50,\bar{x}_{2}=99,\sigma_{2}=6

(b)

Here the test is two-tailed. So for \alpha =0.04, the critical values of the z-test are -2.05 and 2.05.

Decision rule: If z > 2.05 or z<-2.05, reject H0

(c)

Test statistics will be

z=\frac{(\bar{x}_{1}-\bar{x}_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}  \\\\\\z=\frac{(102-99)-(0)}{\sqrt{\frac{5^{2}}{40}+\frac{6^{2}}{50}}}

z=2.59

(d)

The two-tailed nature of the test is shown by the alternative hypothesis.

(e)

The result of the test yields the following P-value: 0.0096

Read more about P-value

brainly.com/question/14790912

#SPJ1

4 0
3 years ago
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