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Rasek [7]
3 years ago
12

The number of bacteria in a sample after ex days is represented using the equation D equals 50,00(1.05) to the power of X by wha

t approximate percent does the population change per day
Mathematics
1 answer:
Nana76 [90]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that :

Change in population per day is Giveb by the exponential equation : 50,00(1.05)

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Find the area of the shaded part of the figure<br>​
kotegsom [21]

Answer:

What is the metrics? like feet squared feet squared metes miles squared miles stuff like that

Step-by-step explanation:

8 0
3 years ago
Solve for x. 2(x + 14) + x = 70a. 11b. 12c. 14d. 17
Mariulka [41]

Hello!

To solve for the variable x, we need to follow the rules of SADMEP. SADMEP is ONLY used when solving algebraic equations. SADMEP is an acronym for subtraction, addition, division, multiplication, exponents, and parentheses. Also, when solving for x, our main goal is to isolate x to one side of the equation.

2(x + 14) + x = 70 (use the distributive property)

2x + 28 + x = 70 (simplify - add)

3x + 28 = 70 (subtract 28 from both sides)

3x = 42 (divide both sides by 3)

x = 14

When solving ANY algebraic equation, we need check our answer. To check your answer, you substitute the x-value, which is 14 in this case, into the original equation and solve using PEMDAS.

2(x + 14) + x = 70 (substitute x = 14)

2(14 + 14) + 14 = 70 (simplify the terms inside the parentheses)

2(28) + 14 = 70 (simplify - multiply)

56 + 14 = 70 (simplify - add alike term)

70 = 70 | This is correct!

Therefore, your final answer is x = 14, which is choice C.

6 0
3 years ago
Compute the line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the l
SIZIF [17.4K]

Answer:

\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}

Step-by-step explanation:

The line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the line segment from (1, 1, 1) to (2, 2, 2) followed by the line segment from (2, 2, 2) to (−9, 6, 5) equals the sum of the line integral of f along each path separately.

Let  

C_1,C_2  

be the two paths.

Recall that if we parametrize a path C as (r_1(t),r_2(t),r_3(t)) with the parameter t varying on some interval [a,b], then the line integral with respect to arc length of a function f is

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{a}^{b}f(r_1,r_2,r_3)\sqrt{(r'_1)^2+(r'_2)^2+(r'_3)^2}dt

Given any two points P, Q we can parametrize the line segment from P to Q as

r(t) = tQ + (1-t)P with 0≤ t≤ 1

The parametrization of the line segment from (1,1,1) to (2,2,2) is

r(t) = t(2,2,2) + (1-t)(1,1,1) = (1+t, 1+t, 1+t)

r'(t) = (1,1,1)

and  

\displaystyle\int_{C_1}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(1+t,1+t,1+t)\sqrt{3}dt=\\\\=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)(1+t)^2dt=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)^3dt=\displaystyle\frac{15\sqrt{3}}{4}

The parametrization of the line segment from (2,2,2) to  

(-9,6,5) is

r(t) = t(-9,6,5) + (1-t)(2,2,2) = (2-11t, 2+4t, 2+3t)  

r'(t) = (-11,4,3)

and  

\displaystyle\int_{C_2}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(2-11t,2+4t,2+3t)\sqrt{146}dt=\\\\=\sqrt{146}\displaystyle\int_{0}^{1}(2-11t)(2+4t)^2dt=-90\sqrt{146}

Hence

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{C_1}f(x,y,z)ds+\displaystyle\int_{C_2}f(x,y,z)ds=\\\\=\boxed{\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}}

8 0
3 years ago
Find the measurement of the indicated angle to the nearest degree
MaRussiya [10]

Answer:

42

Step-by-step explanation:

This time, you'll be doing SOH.

sin (x) = 39/59=0.66

then do sin^-1 (0.66)

x = 42 degrees (think this is correct I hope)

4 0
3 years ago
The local public pool is a rectangle with two semicircles.
Reptile [31]

The area of the surface of the pool is 7322.64 m².

<h3>What is Area of rectangle?</h3>

The area of rectangle is product of length and its breadth.

i.e., length * breadth

Given: Length = 100 m, Width = 52 m and Diameter = 52 m

Area of rectangle,

= 100 × 52

= 5200 m²

Now,

Area of semicircle = 1/2 × πr²

=1/2 × 3.14 × 26²

= 1061.32 m²

Hence, area of the surface of the pool is

= 1061.32 + 1061.32 + 5200

= 7322.64 m²

Learn more about this concept here:

brainly.com/question/15461609

#SPJ1

8 0
2 years ago
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